Given:
Mass of methanol, m = 18754 kg
Density of methanol, ρ = 0.788 g/cm³
By definition, the volume of methanol in the collection tank is
Volume = mass/density
Answer: 2.38 x 10⁷ g/cm³
solution:
The general form of the equation would be A = P x (1/2) ^ (t/h) where A = final amount, P = start amount, t = time (here in days) and h = half-life (has to be same units as t)
a) A = 192 x (1/2) ^ (15/5) = 192 x (1/2) ^3 = 192 x 1/8 = 24 mg
Answer:
gravity pull stuff down...
Explanation:
The balanced equation
for the reaction is:
6 HNCO(l) →
C3N3(NH2)3(l) + 3 CO2(g)
Convert amount of urea
from kg to moles
Molar Mass of urea = 60.06
g/mol so, 113 kg urea contains
113 kg / 60.06 = 1.88
mol urea
From balanced equation 6
moles of urea yields only 1 melamine, so divide the moles of urea by 6.
1.88 / 6 = 0.313 kmol
melamine
Now multiply 0.313 with
molar mass of melamine that is 126 g/mol
126 x 0.313 = 39.438 kg
Yield of overall
reaction is 73% so multiply 39.438 with 0.73
<span>39.438 x 0.73 = 28.799
kg is the answer</span>
Sodium. Oxygen is electronegative and hece pulls bonding electron towards oxygen atom, creating a partial negative charge on the oxygen atom. As unlike charges attract, it is then attracted to the positively charged sodium ion.
