Answer:
2,100
Step-by-step explanation:
Answer:
u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or u = sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) + x tan(A)
Step-by-step explanation:
Solve for u:
(x sin(A) - u cos(A))^2 + (x cos(A) + y sin(A))^2 = x^2 + y^2
Subtract (x cos(A) + y sin(A))^2 from both sides:
(x sin(A) - u cos(A))^2 = x^2 + y^2 - (x cos(A) + y sin(A))^2
Take the square root of both sides:
x sin(A) - u cos(A) = sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or x sin(A) - u cos(A) = -sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)
Subtract x sin(A) from both sides:
-u cos(A) = sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) - x sin(A) or x sin(A) - u cos(A) = -sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)
Divide both sides by -cos(A):
u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or x sin(A) - u cos(A) = -sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)
Subtract x sin(A) from both sides:
u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or -u cos(A) = -x sin(A) - sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)
Divide both sides by -cos(A):
Answer: u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or u = sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) + x tan(A)
Answer: There are 2.25×10³⁴ bacteria at the end of 24 hours.
Step-by-step explanation:
Since we have given that
Number of bacteria initially = 1
It triples in number every 20 minutes.
So, 
So, our equation becomes
We need to find the number of bacteria that it will contain at the end of 24 hours.
So, it becomes,
Hence, there are 2.25×10³⁴ bacteria at the end of 24 hours.
The number after the 9 is larger than 5 so you would round to
200,000.
We have that
<span>1. Find the surface area of a square pyramid with a base length of 24 cm and a height of 16 cm
[surface area]=[area of 4 triangles sides]+[area of square base]
</span>[area of square base]=24*24--------> 576 cm²
[area of one triangles side]
l=slant height
l²=16²+12²-------> l²=400-----------> l=20 cm
[area of one triangles side]=24*20/2--------> 240 cm²
[area of 4 triangles sides]=4*240----------> 960 cm²
[surface area]=[960]+[576]--------> 1536 cm²
the answer part 1) is option B) 1536 cm²
<span>2. Use 3.14 for π and round to the nearest tenth.
</span>Find the surface area of the cylinder<span>
radius=8 in
<span>height= 8 in
</span></span>[surface area]=2*[area of circular base]+[Perimeter of base]*h
[area of circular base]=pi*8²----> 200.96 in²
Perimeter=2*pi*8--------> 50.24 in
[surface area]=2*[200.96]+[50.24]*8-----------> 803.84 in²
the answer Part 2) is the option C) 803.8 in²
<span>3. Find the volume of the cylinder.
</span>[volume of the cylinder]=[area of circular base]*h
[volume of the cylinder]=[200.96]*8---------> 1607.68 in³
the answer Part 3) is the option A.) 1607.7 in.3
<span>4.Find the volume of a rectangular prism with the following dimensions:
Length = 5 mm
Base = 7 mm
Height = 3 mm
</span>
[volume of a rectangular prism]=L*B*H
[volume of a rectangular prism]=5*7*3----------> 105 mm³
the answer part 4) is the option <span>B.) 105 mm3
</span><span>5.Find the volume of the given pyramid.
A large pyramid has a height of 7 yards, radius of 9 yards, and base of 7 yards.
</span>this question is incorrect
the correct question is
5a) A large pyramid has a height of 7 yards and radius of 9 yards. (pyramid with circular base)
or
5b) A large pyramid has a height of 7 yards and base of 7 yards. (pyramid with square base)
<span>we will solve the two cases
</span>
5a) A large pyramid has a height of 7 yards and radius of 9 yards. (pyramid with circular base)
[volume of the pyramid]=pi*r²*h/3---------> pi*9²*7/3---------> 593.46 yd³
the answer Part 5a) is 593.46 yd³
5b) A large pyramid has a height of 7 yards and base of 7 yards. (pyramid with square base)
[volume of the pyramid]=b²*h/3---------> 7²*7/3---------> 114.33 yd³
the answer Part 5b) is 114.33 yd³
<span>6.Find the volume of a square pyramid with a base length of 9 cm and a height of 4 cm.
[</span>volume of a square pyramid]=b²*h/3---------> 9²*4/3-------> 108 cm³
the answer Part 6) is the option <span>B.)1</span>08 cm³
