Number of bricks = volume of wall/volume of 1 brick --------- (both in same units
<span>volume of wall = (15 × 12)(6 × 12)(1 × 12) in³ -------- convert all in inches </span>
<span>volume of 1 brick = 6 × 4 × 2 in³ </span>
<span>Number of bricks = (15 × 12)(6 × 12)(1 × 12)/(6 × 4 × 2) </span>
<span>= (15 × 12)(6 × 3) </span>
<span>= 3240 </span>
Answer:
- The area of rhombus JKLM is 48 units²
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<h3>Given </h3>
- Rhombus JKLM,
- Vertices at J(-2, -4), K(2, 2), L(6, -4), M(2, -10).
<h3>To find </h3>
<h3>Solution</h3>
We know that diagonals of rhombus are perpendicular to each other.
Hence its area is half the product of diagonals.
The diagonals are JL and KM and one of them is vertical and the other one horizontal since x- or y-coordinates are equal in pairs.
Let's find the length of diagonals, using the difference of coordinates:
- JL = 6 - (-2) = 8 units,
- KM = 2 - (-10) = 12 units.
Now find the area:
- A = JL*KM /2 = 8*12 / 2 = 48 units²
The 8 is a, the 3 is b and -45 is c
Plug them into the quadratic formula
Answer is C. the third option
Plug in
When x = - 6, y = ∛[-(-6) + 2] = ∛8 = 2
When x = 1, y = ∛[-1 + 2] = ∛1 = 1
When x = 2, y = ∛[-2 + 2] = ∛0 = 0
When x = 3, y = ∛[-3 + 2] = ∛-1 = -1
When x = 10, y = ∛[-10 + 2] = ∛-8 = -2
<h3>Scott needs to buy 50.24 feet of fencing</h3>
<em><u>Solution:</u></em>
Given that,
Scott wants to buy fencing to place around a circular rock garden
The diameter of the circle is 16 feet
The amount of fencing Scott will need to buy is equal to the circumference of circular garden
<em><u>The circumference of circle is given as:</u></em>
Where, "d" is the circumference of circle
From given,
d = 16 feet
Therefore,
Thus, Scott needs to buy 50.24 feet of fencing