A jar contains 30 marbles. It has 10 red, 6 black and 14 green marbles. Two marbles are drawn, the first is not returned before
1 answer:
<u>Answer:</u>
The correct answer option is P (both green) = 91 / 435
<u>Step-by-step explanation:</u>
We are given that in a jar containing 30 marbles, 10 are red, 6 are black and 14 are green.
Two marbles are drawn and the second one is drawn without returning the first marble and we are to find the probability of getting green marbles both time.
P (both green) = = 91 / 435
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14 of the machine that cost $150 was sold and 8 of the machine that cost $225 was sold.
To solve this problem, we would write a system of linear equations.
- Let x represent the machine that cost $150
- Let y represent the machine that cost $225
We can proceed to write our equations now.
From equation 1
put equation (iii) into (ii)
Since we know the number of y, we can simply substitute it into equation (i) and solve.
From the calculations above, 14 of the machine that cost $150 was sold and 8 of the machine that cost $255 was sold.
Learn more about system of equations here;