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klio [65]
3 years ago
9

Brent bought a reel of thread that is 15.25 metres long. Brent uses 575 centimetres for a project. How much thread in centimetre

s is left on the reel?
Mathematics
1 answer:
GenaCL600 [577]3 years ago
7 0

Answer:

There would be 950 cm of thread left on the reel

Step-by-step explanation:

Here in this question, we are interested in knowing the amount of thread left on the reel.

To answer this question properly, we shall need to be consistent in using our units.

Thus, we need to convert the length of thread on the reel to cm.

Mathematically;

100cm = 1 m

let x cm = 15.25 m

x = 15.25 * 100 = 1525 m

Since 575 cm has been used for a project, the amount of thread in cm left on the reel will be;

1525 cm - 575 cm = 950 cm

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given the functions f(x)=4x^2-1, g(x)=x^2-8x+5, and h(x)=-3x^2-12x +1, rank them from least to greatest based on their axis of s
Lesechka [4]
The formula for axis of symmetry is -b/2a.

For f(x):
0/2(4)
0/8
Axis of symmetry= 0

For g(x)
-(-8)/2(1)
8/2
Axis of symmetry= 4

For h(x)
-(-12)/2(-3)
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Axis of symmetry= -2

Order from least to greatest: -2, 0, 4

Final answer: h(x), f(x), g(x)
7 0
3 years ago
Draw a number line fom -5 to +5 and mark all positive numbers
Gemiola [76]

Answer:

Step-by-step explanation:

i cant draw a number line but we know that integers above 1 are positive. So 1,2,3,4, and 5 are positive and marked

8 0
3 years ago
Read 2 more answers
PLEASE HELP ME PLEASE!!
Harman [31]
  1. Answer:

hypotenuse (h)=?

perpendicular (p)=3

base(b)=2

using pythagoras theorem

h²=p²+b²

h²=3²+2²

h²=9+4

h²=13

h=√13

  • hypotenuse (h)=12
  • perpendicular (p)=10
  • base(b)=?

using pythagoras theorem

b²=h²-p²

b²=12²-10²

b²=144-100

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6 0
2 years ago
Daily high temperatures in St. Louis for the last week were as​ follows: 95​, 92​, 93​, 92​, 95​, 90​, 90 ​(yesterday). ​a) The
hichkok12 [17]

Answer:

a) T = 91.7 degrees

b) T = 90 degrees

c) MAD = 1.9

d) MSE = 5.05

Step-by-step explanation:

Given:

- Daily high temperatures in St. Louis for the last week were as​ follows:

                                   95​, 92​, 93​, 92​, 95​, 90​, 90

Find:

a) Forecast the high temperature today, using a 3-day moving average.

b) Forecast the high temperature today, using a 2-day moving average.

c) Calculate the mean absolute deviation based on a 2-day moving average, covering all days in which you can have a forecast and an actual temperature.

d) The mean squared error for the​ 2-day moving average​

Solution:

a)

- The set of 3 day moving average is as follows:

4.   (95 + 92 + 93) ÷ 3 = 93.33⁰C

5.  (92 + 93 + 92) ÷ 3 = 92.33⁰C

6.  (93 + 92 + 95) ÷ 3 = 93.33⁰C

7.  (92 + 95 + 90) ÷ 3 = 92.33⁰C

8.  (95 + 90 + 90) ÷ 3 = 91.667⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 91.7 degrees

b)

- The set of 2 day moving average is as follows:

3.   (95 + 92) ÷ 2 = 93.5⁰C

4.  (95 + 93) ÷ 2 = 92.5⁰C

5.  (93 + 92) ÷ 2 = 92.5⁰C

6.  (92 + 95) ÷ 2 = 93.5⁰C

7.  (95 + 90) ÷ 2 = 92.5⁰C

8. (90 + 90) ÷ 2 = 90⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 90 degrees

c)

                             Error             Error^2

3.   93.5⁰C            0.5                  0.25

4.   92.5⁰C            0.5                  0.25

5.   92.5⁰C            2.5                  6.25

6.   93.5⁰C            3.5                  12.25

7.   92.5⁰C            2.5                  6.25

8.   90⁰C

- The mean absolute deviation as follows:

                              MAD = Sum of all errors  / 5

                              MAD = (0.5+0.5+2.5+3.5+2.5)  / 5

                              MAD = 1.9

d)

- The mean squared error deviation as follows:

                              MSE = Sum of all error^2  / 5

                              MSE = (0.25+0.25+6.25+12.25+6.25)  / 5

                              MSE = 5.05

4 0
3 years ago
the relationship between the relative size of an earthquake, S, and the measure of the earthquake on the Richter scale, R, is gi
omeli [17]

Answer:

Relative Size, S, is 1584.89


Step-by-step explanation:

The equation is R=log_{10}(S)

Where,

  • R is the measurement in Richter Scale
  • S is the relative size of the earthquare

<u>It is given that in Richter Scale, an earthquake measured 3.2, so R=3.2.</u>

<em>They want to know relative size, S, so we put given information in equation and solve for S:</em>

R=log_{10}(S)\\3.2=log_{10}(S)

<em>Converting to exponential form, we have:</em>

3.2=log_{10}(S)\\S=10^{3.2}\\S=1584.8932

<em>Rounding to nearest hundredth, we have:</em>

S=1584.89

8 0
3 years ago
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