Answer:
Step-by-step explanation:
It's not exactly true.
Suppose s = 4
It is a factor of 16. The greatest common factor between 4 and 16 is not 16. It would only be 4.
So the answer to the question is false.
Answer: 3
Step-by-step explanation:
Answer:
x:y = 1:1 or 2:3
Step-by-step explanation:
By a difference of squares, we get:
(y+x)(y-x)=5(y-x)^2
move all to one side:
(y+x)(y-x) - 5(y-x)^2 = 0
take a common factor of (y - x) out and expand and simply the other factor:
(y - x)[y+x-5(y-x)] = 0
(y - x)(-4y + 6x) = 0
By the null factor rule:
x = y
=> x:y = 1:1
or
6x = 4y
=>
x:y = 4:6
x:y = 2:3
Answer:
a=-16, b=11, c=23
Step-by-step explanation:
The values in the table must satisfy the equation:


Also,

Lastly,
