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3 years ago

Solve the following system of equations: x − 2y = 5 2x − 4y = 10

2 answers:

8 0

x − 2y = 5
2x − 4y = 10

multiply the 1st equation by 2 then
2x - 4y = 10
2x − 4y = 10
-------------------subtract
0 = 0

equation has an infinite number of solutions

Pie3 years ago

7 0

These equation have Infinitely Many Solutions.

I hope this helps.

Have a awesome day. :)

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What's a² + 2a + 2 - a² + 5a?

Eddi Din [679]

Answer:

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3 years ago

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What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7 ?

MariettaO [177]

The slope of a line that is perpendicular to a line whose equation is −2y = 3x + 7 is $\frac{2}{3}$

Solution:

Given that we have to find the slope of the line that is perpendicular to a line whose equation is −2y = 3x + 7

The slope intercept form is given as:

y = mx + c

Where "m" is the slope of line and "c" is the y - intercept

Given equation is:

$-2y = 3x + 7\\\\-y = \frac{3}{2}x + \frac{7}{2}\\\\y = \frac{-3}{2}x - \frac{7}{2}$

On comparing the above equation with slope intercept form,

$m = \frac{-3}{2}$

We know that product of slope of a line and slope of line perpendicular to it is -1

Therefore,

$\frac{-3}{2} \times \text{ slope of line perpendicular to it } = -1\\\\ \text{ slope of line perpendicular to it } = \frac{2}{3}$

Thus slope of line that is perpendicular to given line is $\frac{2}{3}$

3 0

3 years ago

Kendra is determining the distance between the points (6, 8) and (2, –3). Her work is shown below.

Sergeeva-Olga [200]

The x-coordinates need to be subtracted and the y-coordinates need to be subtracted.

The x-coordinates are 6 and 2.
Their subtraction is 6 - 2.
Kendra did this correctly.

The y-coordinates are 8 and -3.
Their subtraction is 8 - (-3) = 8 + 3 = 11.
Kendra did this incorrectly. She should have had 8 - (-3) = 8 + 3 = 11.
Then she'd square 11.
Instead, she subtracted 8 and -3 incorrectly and got 8 - 3 = 5.
Then she squared 5 when she should have squared 11.

5 0

3 years ago

Read 2 more answers

2,7, 12, ... Find the 46th term.

Alex787 [66]

Given is an A.P. in which -

First term,a = 2
Common difference = Second term - First term

$\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad = a_2-a_1$

$\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad = 7-2$

$\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad = 5$

<h3>Solution:- </h3>

nth term of an A.P ,is given by-

$\green{ \underline { \boxed{ \sf{a_n =a+(n-1)d }}}}$

where

$a_n = nth \;term$
a = first term
n = number of term
d = common difference

Putting n = 46

$\begin{gathered}\\\implies \sf a_{46}= 2 + (46-1)\times 5 \\\end{gathered}$

$\begin{gathered}\\\implies \sf a_{46}= 2 + 45\times 5 \\\end{gathered}$

$\begin{gathered}\\\implies \sf a_{46}= 2 + 225 \\\end{gathered}$

$\begin{gathered}\\\implies \sf a_{46}= 227 \\\end{gathered}$

$\longrightarrow$ Therefore, the 46th term is 227

7 0

2 years ago

If the cost of 4 1/2litres of milk is 89 1/2rupees, find the cost of 1 litre of milk. Pls explain too

blagie [28]

Answer:

x=19.88

Step-by-step explanation:

Okay, let's try and create a "table" of what we know, and what we are looking for.

4.5 litres of milk cost 89.5 rupees

1 litre costs x rupees

Obviously, we are looking for x.

The method I'm about to tell you, might be familiar. Imagine that there was a giant X where the words cost and costs are above. There'd be a line connecting 4.5 litres of milk with the rupees we are looking for, and another line connecting 1 litre with the 89.5 rupees.

If we were to form an equation to solve for x, we'd put the connecting terms together, with an "=" between them, so we'd have this:

4.5*x=1*89.5

That's our equation, so let's solve for x.

x=89.5/4.5 => x=19.88 , let's say 20 rupees

3 0

3 years ago