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Norma-Jean [14]
2 years ago
14

Kendra is determining the distance between the points (6, 8) and (2, –3). Her work is shown below.

Mathematics
2 answers:
pogonyaev2 years ago
7 0

Answer:

Her solution is incorrect. She made an error when substituting the y-values into the equation.

Step-by-step explanation: No Cap I know for a fact


Sergeeva-Olga [200]2 years ago
5 0
The x-coordinates need to be subtracted and the y-coordinates need to be subtracted.

The x-coordinates are 6 and 2.
Their subtraction is 6 - 2.
Kendra did this correctly.

The y-coordinates are 8 and -3.
Their subtraction is 8 - (-3) = 8 + 3 = 11.
Kendra did this incorrectly. She should have had 8 - (-3) = 8 + 3 = 11.
Then she'd square 11.
Instead, she subtracted 8 and -3 incorrectly and got 8 - 3 = 5.
Then she squared 5 when she should have squared 11.
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ANSWER

y=-\frac{4}{3}x+\frac{16}{3}


Or

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EXPLANATION


Let us find the gradient of the line:

-3x+4y=4 by rewriting it in the slope intercept form.


\Rightarrow 4y=3x+4


We divide through by 4 now;


\Rightarrow y=\frac{3}{4}x+1


This is now in the form;

y=mx+c

where

m=\frac{3}{4} is he slope.


This implies that the slope of the line that is perpendicular to this line will be the negative reciprocal of m=\frac{3}{4} .


Thus the perpendicular line has slope,

m=\frac{-1}{\frac{3}{4}}= -\frac{4}{3}.


Let the perpendicular line have equation,


y=mx+c

When we substitute the slope we have;


y=-\frac{4}{3}x+c

We substitute the point. (4,0) to find c.


0=-\frac{4}{3}(4)+c


0=-\frac{16}{3}+c


\frac{16}{3}=c

We substitute c to obtain;


y=-\frac{4}{3}x+\frac{16}{3}


Or

3y+4x=16

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