Question

Your town is installing a fountain in the main square. If the water is to rise 28.0 m (91.8 feet) above the fountain, how much pressure must the water have as it moves slowly toward the nozzle that sprays it up into the air? Assume atmospheric pressure equal to 100,000. Pa and g=9.81 m/s2.

Answer 1

Explanation:

Given that,

The water is to rise to a height of 28 meters. Let P is pressure must the water have as it moves slowly toward the nozzle that sprays it up into the air.

We know that, the atmospheric pressure is : $P_a=10^5\ Pa$  

P can be calculated as :

$P=P_a+d\times g\times h$

$P=10^5+1000\times 9.81\times 28$      

P = 374680 Pa    

So, the pressure of 374680 Pascal must the water have as it moves slowly toward the nozzle that sprays it up into the air. Hence, this is the required solution.