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Sonja [21]
3 years ago
8

Jeff’s father is installing a do-it-yourself security system at his house. He needs to get a device from his workshop that conve

rts electric energy to sound energy. Which device is Jeff’s father looking for?
A.
switch
B.
motor
C.
buzzer
D.
bulb
E.
battery
Physics
1 answer:
LekaFEV [45]3 years ago
8 0

<u>Answer:</u>

The correct answer option is C. buzzer.

<u>Explanation:</u>

We know that Jeff's father needs to get a device from his workshop that converts electrical energy to sound energy.

So from the given options, buzzer is the best option Jeff's father can install in his house's security system.

An electric buzzer converts an electrical oscillating voltage into a sound output. In other words, the electrical pulses are converted into sound vibrations.

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A 650 × 10–4 F capacitor stores 24 × 10–3 of charge. What is the potential difference between the plates?
olasank [31]

Answer:

0.369 V

<u>Explanation:</u>

Given :

Capacitance ( c ) = 650 × 10–4 F

Charge ( q ) = 24 × 10–3 C

We are asked to find potential difference ( v )!

We know:

q = c v

= > v = q / c

Putting values here we get:

= > v = ( 24 × 10–3 ) / ( 650 × 10–4 ) V

= > v = 240 / 650 V

= > v = 24 / 65 V

= > v = 0.369 V

Therefore, potential difference between the plates is 0.369 V

8 0
3 years ago
A woman is sitting at a bus stop when an ambulance with a siren wailing at 317 Hz approaches at 69 miles per hour (mph). Assume
Solnce55 [7]

Answer:

a)30.67 m/s

b)348,12 Hz

c)32,34 m/s

d)289,69 Hz

Explanation:

a)

To convert 69 mph to m/s we have:

69\times 1.6=110.4\, Km/h=\frac{110.4}{3.6}=30.67 \, m/s

b)

For a resting receiver and an approaching source we have the following Doppler formula:

f=f_0\frac{c}{c-v_s}

where v_s is the source, and c is the speed of sound, f the perceived frequency and f_0 the frequency as perceived by the source. Plugging all the relevant values we get:

f=348,12 \, Hz

c)

Using the same formula as above and solving for v_s we have:

v_s=c\frac{f-f_0}{f}=32,34 \, m/s

d)

Now we have another Doppler formula for a source that is moving away from the receiver:

f=f_0\frac{c}{c+v_s}=289.69 Hz

3 0
4 years ago
Read 2 more answers
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