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dolphi86 [110]
3 years ago
14

How to solved percentages?

Mathematics
1 answer:
MrMuchimi3 years ago
3 0
Imagine you have a pizza the whole pizza is 100%
Then the pizza is sliced on 8 equal parts that means one slice now presents a part of whole pizza 1/8 out of 8/8 in this case one slice presents 12.5% of 100% pizza.
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Pls I need help with this
LiRa [457]

Answer:

third side = 4

Step-by-step explanation:

third side is hypoenuse as it is opposite to 90 degree.

using pythagoras theorem

(perpendicular)^2 + (base)^2 = (hypotenuse)^2

2^2 + (2\sqrt{3 )^2 = hypotenuse^2

4 + 4*3 = hypotenuse^2

16 = hypotenuse^2

\sqrt{16} = hypotenuse

4 = hypotensue

7 0
3 years ago
Pedro, Alex, and Jaime are having a three-point contest. Each boy takes six turns and records the number of three-pointers he sh
bazaltina [42]
First, reorder the numbers for each person. 
The median is basically the middle number. If there are 2 middle numbers, then take the average of the two of them. 

Pedro: 4, 5, 6, 7, 8, 9    
The 2 middle numbers are 6 and 7. The average of 6 and 7 is 6.5 .
Median = 6.5

Alex: 3, 5, 5, 5, 9, 9
The 2 middle numbers are 5 and 5; so basically, the average is 5.
Median = 5

Jaime: 3, 4, 6, 8, 8, 9
The 2 middle numbers are 6 and 8 and thus, the average is 7.
Median = 7



So the answer should be Jaime. 
7 0
3 years ago
Read 2 more answers
I will give BRAINLIEST to whoever is correct.
Shtirlitz [24]
The answer would be ab+ac
4 0
4 years ago
Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi
ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles  carry just one person.    

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

\mu = np = 92(0.64) = 58.88

\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60

We have to evaluate the probability that more than 47 cars carry just one person.

P(x \geq 47)

After continuity correction, we will evaluate

P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)

= 1 - P(z \leq -2.6913)

Calculation the value from standard normal z table, we have,  

P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0
3 years ago
Plz help this is due tomorrow
kkurt [141]
7:8 Purl Stitches I believe ! :)
4 0
3 years ago
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