1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:

2.

3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
Answer: but I need the points sorri
Answer:
X=6
FG=31
GH=22
Step-by-step explanation:
Equation: FG+GH=FH
rewrite with values
4x+7 + 5x-8 = 53
combine like terms
9x-1 = 53
add 1 to both sides
9x = 54
divide by 9
x = 6
use 6 end solve for FG and GH
FG = 4(6) + 7 = 31
GH = 5(6) - 8 = 22
Check your answers.. Do FG and GH add up to equal FH (53)?
31 + 22 = 53
I hope this made sense.
Your answer is C If not A have a good day
Since f(x) is a polynomial with 3rd degree, then it will have 3 roots (zeroes)
One of them is real and the other two are complex conjugate roots
Since the real root is 4, then
x = 4
Since the complex root is (1 - i), then
The other root will be the conjugate of it (1 + i)
x = (1 - i)
x = (1 + i)
To find f(x) we will multiply the three factors of it
We can get the factors from the zeroes

Subtract 4 from both sides

The first factor is (x - 4)

The second factor is (x - 1 + i)
The third factor is (x - 1 - i)

We will multiply them to find f(x)

Multiply it by (x - 4)

The answer is