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Hatshy [7]
3 years ago
14

What is the word form of 3,552,308,725?

Mathematics
2 answers:
77julia77 [94]3 years ago
7 0
Three Billion, Five Hundred And Fifty Two Million, Three Hundred And Eight Thousand, Seven Hundred And Twenty Five.
Serhud [2]3 years ago
4 0
Three-billion, five hundred fifty two million, three hundred eight thousand, seven hundred twenty five
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A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic
goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event <em>E</em>_{i}, of the sample space <em>S,</em> given that another event <em>A</em> has already occurred is:

P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}

The law of total probability states that, if events <em>E</em>₁, <em>E</em>₂, <em>E</em>₃... are parts of a sample space then for any event <em>A</em>,

P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}

Denote the events as follows:

<em>X</em> = fetus have a chromosome abnormality.

<em>Y</em> = the test is positive

The information provided is:

P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85

Using the above the probabilities compute the remaining values as follows:

P(X^{c})=1-P(X)=1-0.04=0.96

P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10

P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})

          =(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}

             =\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}

             =0.20

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

6 0
3 years ago
Heyy could you help me out with this question I have been stuck in this question??​
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I think the first box is perpendicular good luck
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2 years ago
8. Lisa types 6 pages in 36 minutes. Frank types 5 pages in 30 minutes. Do they type at the same rate? Use a proportion to expla
qaws [65]

Answer:

Yes

Step-by-step explanation:

Lisa and Frank type at the same rate.

They both type 1 page every six minutes.

Lisa types 6 pages every 36 minutes, and if we divide the minutes by the pages, we get

\frac{36}{6} = 6

And Frank types 5 pages ever 30 minutes, when we divide we get

\frac{30}{5} = 6

3 0
3 years ago
Find the area of the shape​
Annette [7]

Answer:

36 + 36 = 72

Step-by-step explanation:

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3 years ago
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Answer:

6

Step-by-step explanation:

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