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3 years ago

What is the word form of 3,552,308,725?

Mathematics

2 answers:

77julia77 [94]3 years ago

7 0

Three Billion, Five Hundred And Fifty Two Million, Three Hundred And Eight Thousand, Seven Hundred And Twenty Five.

Serhud [2]3 years ago

4 0

Three-billion, five hundred fifty two million, three hundred eight thousand, seven hundred twenty five

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Please help ! :)

kolezko [41]

Answer: Third option.

Step-by-step explanation:

You know that:

$\frac{Area\ of\ sector}{Area\ of\ circle}=\frac{n}{360\°}$

Where "n" is the Central angle measured in degrees.

In this case, let be:

$Area\ of\ sector=A_s\\Area\ of\ Circle=A_c$

Rewriting the formula:

$\frac{A_s}{A_c}=\frac{n}{360\°}$

Now, you need to solve for $A_c$ :

$A_s=(\frac{n}{360\°})(A_c)\\\\A_c=(A_s)(\frac{360\°}{n})$

Given the data shown in the picture attached, you can identify that:

$A=A_s=6\pi \ in^2\\\\n=40\°$

Then, you can substitute these values into the equation (Use $\pi =3.14$ ):

$A_c=(6*3.14\ in^2)(\frac{360\°}{40\°})\\\\A_c=169.56\ in^2\\\\A_c\approx170\ in^2$

Therefore, the entire mirror will cover $170\ in^2$

8 0

3 years ago

Classify the following triangle. Check all that apply.

Rashid [163]

Answer: That is a right triangle sir

Step-by-step explanation:

You see the box in the corner of the triangle. Well it's not just a box that box measures 90 degrees and a right triangle is 90 degrees so there is your answer.

8 0

3 years ago

Read 2 more answers

The number of people arriving for treatment at an emergency room can be modeled by a Poisson Distribution with a rate parameter

AlekseyPX

Answer:

a) 0.052 = 5.2% probability that exactly three arrivals occur during a particular hour

b) 0.971 = 97.1% probability that at least three people arrive during a particular hour

c) 5.25 people are expected to arrive during a 45-min period

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Poisson Distribution with a rate parameter of seven per hour.

This means that $\mu = 7$

(a) What is the probability that exactly three arrivals occur during a particular hour?

This is P(X = 3).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 3) = \frac{e^{-7}*7^{3}}{(3)!} = 0.052$

0.052 = 5.2% probability that exactly three arrivals occur during a particular hour.

(b) What is the probability that at least three people arrive during a particular hour? (Round your answer to three decimal places.)

Either less than three people arrive, or at least three does. The sum of the probabilities of these events is 1. So

$P(X < 3) + P(X \geq 3) = 1$

We want $P(X \geq 3)$ , which is

$P(X \geq 3) = 1 - P(X < 3)$

In which

$P(X \geq 3) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-7}*7^{0}}{(0)!} = 0.001$

$P(X = 1) = \frac{e^{-7}*7^{1}}{(1)!} = 0.006$

$P(X = 2) = \frac{e^{-7}*7^{2}}{(2)!} = 0.022$

$P(X \geq 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.001 + 0.006 + 0.022 + 0.029$

$P(X \geq 3) = 1 - P(X < 3) = 1 - 0.029 = 0.971$

0.971 = 97.1% probability that at least three people arrive during a particular hour

(c) How many people do you expect to arrive during a 45-min period?

During an hour(60 minutes), 7 people are expected to arrive. So, using proportions:

$\frac{45*7}{60} = \frac{3*7}{4} = \frac{21}{4} = 5.25$

5.25 people are expected to arrive during a 45-min period

5 0

3 years ago

How to find the missing variable?

forsale [732]

50 + 3x = 7x + 12
This is because of the exterior angle theorem.

8 0

3 years ago

Which statements about the data sets are true? Check all that apply.

Yuri [45]

Answer: 2, 3, 4, 5

Step-by-step explanation:

I just did it i'm positive it correct :)

Hope this helps.

7 0

3 years ago