1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Verdich [7]
3 years ago
13

I need the answer for question 15 a and b

Mathematics
2 answers:
castortr0y [4]3 years ago
8 0
A Is 14 b I'm
Not sure but 14 is my answer for A
trasher [3.6K]3 years ago
7 0
A is 14 total 
B is yes because the gained 11 and lost 3 which means they gained 8 after taking away the ones lost and they are still on the positive side so they keep th ball.

You might be interested in
PLEASE HELP!!!!!!<br> who every gets it right I will give brainly and 20 points
Sindrei [870]

Unit price:

$3.03 for a gallon of gass

$0.05 per ounce of soap

$0.75 per bag of popcorn

Not a Unit Price:

$20 for 5 books

$33.00 for 2 avocadoes

hoped that helped

8 0
2 years ago
Can anyone help me integrate :
worty [1.4K]
Rewrite the second factor in the numerator as

2x^2+6x+1=2(x+2)^2-2(x+2)-3

Then in the entire integrand, set x+2=\sqrt3\sec t, so that \mathrm dx=\sqrt3\sec t\tan t\,\mathrm dt. The integral is then equivalent to

\displaystyle\int\frac{(\sqrt3\sec t-2)(6\sec^2t-2\sqrt3\sec t-3)}{\sqrt{(\sqrt3\sec t)^2-3}}(\sqrt3\sec t)\,\mathrm dt
=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\sqrt{\sec^2t-1}}\,\mathrm dt
=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\sqrt{\tan^2t}}\,\mathrm dt
=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{|\tan t|}\,\mathrm dt

Note that by letting x+2=\sqrt3\sec t, we are enforcing an invertible substitution which would make it so that t=\mathrm{arcsec}\dfrac{x+2}{\sqrt3} requires 0\le t or \dfrac\pi2. However, \tan t is positive over this first interval and negative over the second, so we can't ignore the absolute value.

So let's just assume the integral is being taken over a domain on which \tan t>0 so that |\tan t|=\tan t. This allows us to write

=\displaystyle\int\frac{(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\sec t}{\tan t}\,\mathrm dt
=\displaystyle\int(6\sqrt3\sec^3t-18\sec^2t+\sqrt3\sec t+6)\csc t\,\mathrm dt

We can show pretty easily that

\displaystyle\int\csc t\,\mathrm dt=-\ln|\csc t+\cot t|+C
\displaystyle\int\sec t\csc t\,\mathrm dt=-\ln|\csc2t+\cot2t|+C
\displaystyle\int\sec^2t\csc t\,\mathrm dt=\sec t-\ln|\csc t+\cot t|+C
\displaystyle\int\sec^3t\csc t\,\mathrm dt=\frac12\sec^2t+\ln|\tan t|+C

which means the integral above becomes

=3\sqrt3\sec^2t+6\sqrt3\ln|\tan t|-18\sec t+18\ln|\csc t+\cot t|-\sqrt3\ln|\csc2t+\cot2t|-6\ln|\csc t+\cot t|+C
=3\sqrt3\sec^2t-18\sec t+6\sqrt3\ln|\tan t|+12\ln|\csc t+\cot t|-\sqrt3\ln|\csc2t+\cot2t|+C

Back-substituting to get this in terms of x is a bit of a nightmare, but you'll find that, since t=\mathrm{arcsec}\dfrac{x+2}{\sqrt3}, we get

\sec t=\dfrac{x+2}{\sqrt3}
\sec^2t=\dfrac{(x+2)^2}3
\tan t=\sqrt{\dfrac{x^2+4x+1}3}
\cot t=\sqrt{\dfrac3{x^2+4x+1}}
\csc t=\dfrac{x+2}{\sqrt{x^2+4x+1}}
\csc2t=\dfrac{(x+2)^2}{2\sqrt3\sqrt{x^2+4x+1}}

etc.
3 0
3 years ago
Maria spent the day working at a DVD shop. They run a sale with $10 DVDs and $12 DVDs. Her boss wants to know the total number o
solniwko [45]

575

575 could work if each dvd is worth 10$ each

7 0
3 years ago
Ralph bought 6 cds at the cost of $17.75 each how much did the cds cost altogether
daser333 [38]

I think its $106.5 just add 17.75 6 times


7 0
3 years ago
Read 2 more answers
Divide 3.7÷0.006 round the answer the nearest hundredth?
Julli [10]
First divide 3.7 by 0.006
Which is 616.666
The last 6 is the thousandths place. If it is 5 or bigger then the number to the left is rounded up. If its lower than 5 you round down

Since 6 is over 5 we tound up
616.67
6 0
3 years ago
Other questions:
  • Two car-rental agencies are competing for business. Mertz charges $35 a day and $0.15 per mile, and Mavis charges $20 a day and
    13·1 answer
  • A. What is the approximate perimeter of the concrete region?
    9·1 answer
  • How do box and whisker plots work?
    8·2 answers
  • To get from the post office to the library, Sindy walked due north and then due east. The distance Sindy walked east is 20 meter
    15·2 answers
  • If you multiply 1m times unlimedted what will u get
    9·2 answers
  • A bakery offers a sale price of $3.30 for 3 muffins. What is the price per dozen?
    9·1 answer
  • Please only responded if you can help
    12·2 answers
  • A group of 17 students participated in a quiz competition. Their scores are shown below:
    15·1 answer
  • What is the value of p in the proportion below?
    7·2 answers
  • Skye ran rlaps today at soccer practice. Nadine ran five fewer laps than Skye. If Nadine ran eight laps at practice, which of th
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!