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Rom4ik [11]
3 years ago
6

Find the surface area of the pyramid shown to the nearest whole number.

Mathematics
1 answer:
Snezhnost [94]3 years ago
7 0

Answer:

<h3>The answer is option A</h3>

Step-by-step explanation:

Surface area of a pyramid =

area of base + area of triangular faces

Since it's a square based pyramid

It's surface area is

area of base + 4( area of one triangular face)

Since the square has equal sides

<u>For square base </u>

Area of a square = l²

where l is the length

From the question l = 5

So we have

Area of square base = 5² = 25ft²

<u>For one of the triangular face</u>

Area of a triangle = ½ × base × height

base = 5

height = 6

Area = ½ × 5 × 6 = 15ft²

So the surface area of the pyramid is

25 + 4(15)

= 25 + 60

We have the final answer as

<h3>Surface area = 85 ft²</h3>

Hope this helps you

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Answer: The quotient is (x-2).

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Since we have given that

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Now, we have to find the quotient of the above expression.

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Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)

Now, we will divide the above simplest form with g(x):

\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2

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I hope this helps you



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Step-by-step explanation:

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ck−kq+pq=dp

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