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Rom4ik [11]
3 years ago
6

Find the surface area of the pyramid shown to the nearest whole number.

Mathematics
1 answer:
Snezhnost [94]3 years ago
7 0

Answer:

<h3>The answer is option A</h3>

Step-by-step explanation:

Surface area of a pyramid =

area of base + area of triangular faces

Since it's a square based pyramid

It's surface area is

area of base + 4( area of one triangular face)

Since the square has equal sides

<u>For square base </u>

Area of a square = l²

where l is the length

From the question l = 5

So we have

Area of square base = 5² = 25ft²

<u>For one of the triangular face</u>

Area of a triangle = ½ × base × height

base = 5

height = 6

Area = ½ × 5 × 6 = 15ft²

So the surface area of the pyramid is

25 + 4(15)

= 25 + 60

We have the final answer as

<h3>Surface area = 85 ft²</h3>

Hope this helps you

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tino4ka555 [31]
Since the only two corresponding side you have are 10 units and 4 units, you can divide these two numbers to get the scale factor.

10÷4=2.5

next you find the sides corresponding to X Y and Z and if it is on the bigger figure you divide, if it is on the smaller side you multiply

X corresponds with 5 (so ×2.5)
Y corresponds with 8 (÷2.5)
Z corresponds with 10 (÷2.5)

final answer is X=12.5 Y=3.2 Z=4

I try to explain the question and give the answer, I hope this helps!
5 0
3 years ago
How much would you need to deposit in an account now in order to have $4000 in the account in 15 years? Assume the account earns
Finger [1]

Answer:

$2500

Step-by-step explanation:

CA=p(1+MR÷1200)

4000=p(1+180×4÷1200) 15 yrs =15×12=180 month

4000=1.6p

p=4000÷1.6

p=2500

please give me brainliest

5 0
2 years ago
Need some help please
zaharov [31]

Answer:

Step-by-step explanation:

number 2

6 0
3 years ago
4x^2-5x-15=0 how to find the vertex and y intercept
mezya [45]
ax^2+bx+c=0\\\\the\ vertex:\left(\frac{-b}{2a};\frac{-(b^2-4ac)}{4a}\right)\\\\y-intrcept=c\\=======================================\\\\4x^2-5x-15=0\\\\a=4;\ b=-5;\ c=-15\\\\\frac{-b}{2a}=\frac{-(-5)}{2\cdot4}=\frac{5}{8};\ \frac{-(b^2-4ac)}{4a}=\frac{-[(-5)^2-4\cdot4\cdot(-15)]}{4\cdot4}=-\frac{265}{16}\\\\\boxed{the\ vertex:\left(\frac{5}{8};-\frac{265}{16}\right)}\\\\\boxed{y-intercept:-15}
5 0
3 years ago
Hmmm..........................................................................................................
AveGali [126]
The 3rd one down is the answer
7 0
3 years ago
Read 2 more answers
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