A segment has an endpoint at (2, 4) and a midpoint at (4. 2). What are the coordinates of the other endpoint (2, 10) B. (3, 1) C
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The question is incomplete. The map is attached as a photo and here is the complete question:
a. What is the actual distance between Saugerties and
Kingston? ___________________________
b. Catskill is 15 miles from Saugerties. What would the
distance on the map be? ___________________________
c. On another map, the distance between Saugerties and
Kingston is 2 inches. What would the distance from Saugerties to
Catskill be on this map? __________________
Since you have asked the answer for part (c) only, here is the answer:
Answer:
<u>The distance from Saugerties to Catskill would be </u><u>3 inches</u><u> on this map.</u>
Step-by-step explanation:
On the given map, the distance between Saugerties and Kingston is 4 inches and the scale is <u>1 inch = 2.5 miles.</u>
To calculate the actual distance in miles between Saugerties and Kingston, consider the given scale:
1 inch ---------- 2.5 miles
4 inches ------ x miles
Cross multiplying:
1x = 2.5 x 4
x = 10 miles
The actual distance between Saugerties and Kingston is 10 miles.
On another map, the distance between Saugerties and Kingston is 2 inches. Which means the scale is 2 inches = 10 miles. So 1 inch = 10/2 = 5 miles
The scale on the other map is 1 inch = 5 miles.
Catskill is 15 miles from Saugerties (given in the previous part). So on the map:
1 inch -------- 5 miles
y inch ------- 15 miles
Cross multiplying:
15 = 5y
y = 15/5
<u>y = 3 inches.</u>
The distance from Saugerties to Catskill would be 3 inches on this map.
Answer:
3/11
Step-by-step explanation:
given that a cell phone company has three different production sites
Site name 1 2 3 Total
Production 60% 30% 10% 100%
Recalled 5% 7% 9%
Prob for recall 0.003 0.021 0.009 0.033
Total probability for recall = 0.033
Prob for recall and came from site 3 = 0.009
So required probability
= If a randomly selected cell phone has been recalled, what is the probability that it came from Site 3
=