If you were to take the universe's temperature, what would the reading be?

At a certain location, Earth has a magnetic field of 0.60 ✕ 10−4 T, pointing 75° below the horizontal in a north-south plane. A

saveliy_v [14]

Answer with Explanation:

We are given that

Magnetic field,B= $0.6\times 10^{-4} T$

$\theta=75^{\circ}$

Length of wire,l=15 m

Current,I=19 A

a.We have to find the magnitude of magnetic force and direction of magnetic force.

Magnetic force,F= $IBlsin\theta$

Using the formula

$F=0.6\times 10^{-4}\times 15\times 19sin75$

$F=16.5\times 10^{-3} N$

Direction= $tan\theta=cot(90-75)=tan15^{\circ}$

$\theta=15^{\circ}$

15 degree above the horizontal in the northward direction.

5 0

3 years ago

A blue supergiant star has surface temperature 27 kK and has total power output 100000 times that of the Sun.

Free_Kalibri [48]

Answer:

Wien peak ( λmax ) is 107.40 nm

radius of super giant is 1.086 × $10^{10}$ m

Explanation:

given data

temperature 27 kK

power = 100000 times of Sun

Sun radius = 6.96 × 10^8 m

to find out

Wien peak ( λmax ) and radius of supergiant (r)

solution

we will apply here first wien law to find Wien peak that is

λmax = b / t

λmax = 2.9 × $10^{-3}$ / 27000 = 1.0740 × $10^{-7}$

so Wien peak ( λmax ) is 107.40 nm

and

now we apply steafay law that is

P = σ × A × $T^{4}$ .........................1

and we know total power output 100000 time of Sun

so we say

4πr²s $T^{4}$ = 100000 × 4πR²s $Ts^{4}$

r² = 100000 × R² $Ts^{4}$ / $T^{4}$

put here value

r² = 100000 × (6.96× $6000^{8}$ )² × $6000^{4}$ / $27000^{4}$

r² = 1.18132 × $10^{20}$

r = 1.086 × $10^{10}$ m

so radius of super giant is 1.086 × $10^{10}$ m

3 0

4 years ago

QUESTION 1

Sveta_85 [38]

distance from the Sun of 2.77 astronomical units or about 414 million km 257 million miles and orbiting period of 4.62 years

7 0

3 years ago

Why is si unit called coherent system

Sladkaya [172]

Answer:

The SI system is also called coherent system of units because of the following reasons: ... 1 Newton (SI unit of Force) = 1 Kg (SI unit of mass) x 1 m (SI unit of distance) / s2 (SI unit of time) , therefore 1 Newton is a coherent unit of Force.

HOPE ITS HELP

<h2>#BRAINLEST</h2>

6 0

3 years ago

La resistencia de un termómetro de platino es de 6Ω a30°C. Hallar su valor correspondiente a 100°C,sabiendo que el coeficiente d

Sonja [21]

Respuesta:

7,6 Ω

Explicación:

Paso 1: Información dada

Resistencia a 30 °C (R₀): 6 Ω

Coeficiente de temperatura (α): 0,00392 °C⁻¹

Paso 2: Hallar la resistencia (R) a 100 °C

Podemos ver la relación entre la resistencia de un material y la temperatura usando la siguiente ecuación.

R = R₀ (1 + α × ΔT)

R = 6 Ω (1 + 0,00392 °C⁻¹ × (100 °C - 30 °C)) = 7,6 Ω

6 0

3 years ago