Question

A 4.5-kg object oscillates on a horizontal spring with an amplitude of 3.8 cm. Its maximum acceleration is 26 m/s2 . Find (a) the force constant k, (b) the frequency, and (c) the period of the motion.

Answer 1

Answer:

F = - K X     force constant for spring

a = F / m      maximum acceleration

F = 4.5 kg * 26 m/s^2 = 117 Newtons

(A)  K = 117 N / .038 m = 3079 N/m

ω = (K/M)^1/2 = (117/5)^1/2 = 4.84 / sec

(B) f = ω / 2 pi = 4.84 / 6.28 = .77 /sec

(C) P = 1 / f = 1/.77   = 1.30 sec