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Aleksandr [31]
2 years ago
14

A 4.5-kg object oscillates on a horizontal spring with an amplitude of 3.8 cm. Its maximum acceleration is 26 m/s2 . Find (a) th

e force constant k, (b) the frequency, and (c) the period of the motion.
Physics
1 answer:
zimovet [89]2 years ago
3 0

Answer:

F = - K X     force constant for spring

a = F / m      maximum acceleration

F = 4.5 kg * 26 m/s^2 = 117 Newtons

(A)  K = 117 N / .038 m = 3079 N/m

ω = (K/M)^1/2 = (117/5)^1/2 = 4.84 / sec

(B) f = ω / 2 pi = 4.84 / 6.28 = .77 /sec

(C) P = 1 / f = 1/.77   = 1.30 sec

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The fact that the magnetic field generates a force perpendicular to the instantaneous velocity of the particle has implications
Anna35 [415]

Answer:

<h2>c. remain constant</h2>

Explanation:

Such type of field that is created by the magnetic condition is known as magnetic field. Such type of the developed by electrical condition and some other ways. This filed has many important roles in electrical engineering and some other fields.  

When any magnetic field acts in perpendicular condition then no work is done by the field. Thus the kinetic energy and speed of the particle remain in constant condition.

3 0
3 years ago
Is this answer correct?
alisha [4.7K]
Yes the answer is correct
4 0
3 years ago
A glass rod and a steel rod are of equal length at 0C. At 100C they differ in length by
NeX [460]

The given lengths at 0 °C are 2.5 m

Let l₀ be the given lengths of the glass and steel rods at 0 °C. Let l and l' be the lengths of the glass and steel rods at 100 °C respectively.

From our expression for linear expansivity,

l = l₀ + l₀αΔθ where α = linear expansivity of glass = 0.000008/°C and Δθ = temperature change = θ - θ' where θ = 100 °C and θ' = 0 °C. So, Δθ = 100 °C - 0 °C = 100 °C.

Also,

l' = l₀ + l₀α'Δθ where α' = linear expansivity of steel = 0.000012/°C and Δθ = temperature change = θ - θ' where θ = 100 °C and θ' = 0 °C. So, Δθ = 100 °C - 0 °C = 100 °C.

Since the difference in their lengths at 100 °C = 0.001 m, we have that

l - l' = l₀ + l₀αΔθ - (l₀ + l₀α'Δθ)

l - l' = l₀ + l₀αΔθ - l₀ - l₀α'Δθ)

l - l' = l₀αΔθ - l₀α'Δθ

l - l' = l₀(α- α')Δθ

Making l₀ subject of the formula, we have

l₀ = (l - l')/[(α- α')Δθ]

Substituting the values of the variables into the equation, we have

l₀ = (l - l')/[(α- α')Δθ]

l₀ = 0.001 m/[(0.000008/°C - 0.000012/°C)100 °C.]

l₀ = 0.001 m/[(-0.000004/°C)100 °C.]

l₀ = 0.001 m/-0.0004

l₀ = -2.5 m

Neglecting the negative sign,

l₀ = 2.5 m

So, the given lengths at 0 °C are 2.5 m

Learn more about linear expansion here:

brainly.com/question/14089545

6 0
2 years ago
Can you help and explain these for me?
ollegr [7]
Yes I can do you want me to
8 0
3 years ago
Energy that flows from an objective with a higher temperature to an object with a lower temperature
dalvyx [7]
That's THERMAL energy, often referred to as "heat".
7 0
3 years ago
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