Answer:
(A) ratio of electric force to weight will be 
(b) Electric field will be 
Explanation:
We have given mass of bee = 100 mg = 
Charge on bee 
Electric field E = 100 N/C
Weight of the bee 
Electric force on the bee 
So the ratio of electric force on the bee and weight is 
(B) To hold the bee in air electric force must be equal to weight of bee
So 


E=kq/r^2
q=(E*r^2)/k
q=(.086N/C)(1.7m^2)/(8.99*10^9N*m^2/C^2)
q=2.76*10^-11 C
q=2.8*10^-11 C
Answer:
Correct answer: Kinetic energy of rotation, kinetic energy of translation and potential energy
Explanation:
Before it began to rotate it possessed potential energy. After being released from the rest it starts to roll on the roof and get kinetic energy of rotation, kinetic energy of translation along with potential energy.
God is with you!!!
<span> S = k ln(W)
= 1.38*10^-23 J/K * ln(4)
= 1.91*10^-23 J/K</span>
so it will be c