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3 years ago

How many different plant and animal species can be found in tropical rainforests

Physics

2 answers:

wariber [46]3 years ago

7 0

Answer:

Explanation:

Elena-2011 [213]3 years ago

4 0

Over 200,000 species of plants can live in rain forests

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Joey ran at a speed of 18 km/h for a total of 2 hours. How much distance did he<br> cover?

GenaCL600 [577]

Answer:

Explanation:

The distance covered by an object given it's velocity and time taken can be found by using the formula

distance = velocity × time

From the question we have

distance = 18 × 2

We have the final answer as

Hope this helps you

8 0

3 years ago

A parallel circuit containing two bulbs and a bell has three paths for the current flow. If the first bulb in the circuit burns

yanalaym [24]

Answer:

Explanation:

Since the circuit is in parallel there will be no effect on the other loads.

3 0

3 years ago

A 6.0 kg box slides down an inclined plane that makes an angle of 39° with the horizontal. If the coefficient of kinetic frictio

Blababa [14]

Answer:

(B) 1.6 m/s^2

Explanation:

The equation of the forces acting on the box in the direction parallel to the slope is:

$mg sin \theta - \mu N = ma$ (1)

where

$mg sin \theta$ is the component of the weight parallel to the slope, with m = 6.0 kg being the mass of the box, g = 9.8 m/s^2 being the acceleration of gravity, $\theta=39^{\circ}$ being the angle of the incline

$\mu N$ is the frictional force, with $\mu = 0.6$ being the coefficient of kinetic friction, N being the normal reaction of the plane

a is the acceleration

The equation of the force along the direction perpendicular to the slope is

$N-mg cos \theta =0$

where $mg cos \theta$ is the component of the weight in the direction perpendicular to the slope. Solving for N,

$N=mg cos \theta$

Substituting into (1), solving for a, we find the acceleration:

$a=gsin \theta- \mu g cos \theta=(9.8)(sin 39^{\circ})-(0.6)(9.8)(cos 39^{\circ})=1.6 m/s^2$

6 0

4 years ago

A 17 kg box experiences an applied force of +175 N and a force of friction of -125 N. While experiencing these unbalanced forces

Flura [38]

Answer: (b)

Explanation:

Given

Mass of box $m=17\ kg$

Applied force $F=175\ N$

Friction force $f=-125\ N$

Box travels a distance of $s=15\ m$

time taken $t=5.25\ s$

Net unbalanced force $F_{net}=175-125=50\ N$

Work done by the unbalanced force

$\Rightarrow W=F_{un}\cdot s\\\Rightarrow W=50\times 15\\\Rightarrow W=750\ N$

Power developed by unbalanced force

$\Rightarrow P=\dfrac{W}{t}\\\\\Rightarrow P=\dfrac{750}{5.25}\\\\\Rightarrow P=142.85\approx 1423\ W$

Thus, option (b) is correct.

7 0

3 years ago

You serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 35 m/s. The ball has __________________

Elden [556K]

Answer:

The ball has kinetic energy

the kinetic energy is 945 J

Explanation:

4 0

3 years ago

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