A= 2pi(radius)(height)+2pi(radius)^2
Mark me as brainiest! <3
0.19579831 (that's what my math app said the estimate was)
A Pythagorean triple consists of three positive integers a, b, and c, such that a2 + b2 = c2. Such a triple is commonly written (a, b, c), and a well-known example is (3, 4, 5). If (a, b, c) is a Pythagorean triple, then so is (ka, kb, kc) for any positive integer k.
Answer:
49/8 is the value of k
Step-by-step explanation:
We have the system
x = -2y^2 - 3y + 5
x=k
We want to find k such that the system intersects once.
If we substitute the second into the first giving us k=-2y^2-3y+5 we should see we have a quadratic equation in terms of variable y.
This equation has one solution when it's discriminant is 0.
Let's first rewrite the equation in standard form.
Subtracting k on both sides gives
0=-2y^2-3y+5-k
The discriminant can be found by evaluating
b^2-4ac.
Upon comparing 0=-2y^2-3y+5-k to 0=ax^2+bx+c, we see that
a=-2, b=-3, and c=5-k.
So we want to solve the following equation for k:
(-3)^2-4(-2)(5-k)=0
9+8(5-k)=0
Distribute:
9+40-8k=0
49-8k=0
Add 8k on both sides:
49=8k
Divide both sides by 8"
49/8=k
Hello!
You can put x into the answer choices to see if we get y
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y = -x + 9
y = -(-5) + 9
y = 5 + 9
y = 14
This could be a answer
y = -(-2) + 9
y = 2 + 9
y = 11
y = -(1) + 9
y = -1 + 9
y = 8
y = -(4) + 9
y = -4 + 9
y = 5
we got y every time so the answer is the first one
The answer is A) y = -x + 9
Hope this helps!
