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Andru [333]
3 years ago
13

The time that it takes to service a car is an exponential random variable with rate 1. (a) If Lightning McQueen (L.M.) brings hi

s car in at time 0 and Sally Carrera (S.C) brings her car in at time t, what is the probability that S.C.’s car is ready before L.M.’s car? Assume that service times are independent and service begins upon arrival of the car. Be sure to: 1) define all random variables used. 2) explain how independence of service times plays a part in your solution. 3) show all integration steps. (b) If both cars are brought in at time 0, with work starting on S.C.’s car only when L.M.’s car has been completely serviced, what is the probability that S.C.’s car is ready before time 2?
Mathematics
1 answer:
Genrish500 [490]3 years ago
4 0

Answer:I’m not really sure

Step-by-step explanation:

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just take away 14 to 48 and put a negative infront

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3 years ago
Evaluate the following expression (a + b)^0
elixir [45]

Answer:

So, (a + b)^0=1

Step-by-step explanation:

(a + b)^0

To evaluete this expression we apply exponential property

x^0=1

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for example, 3^0 =1

5^0=1

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3 0
3 years ago
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PLEASE HELP WILL MARK BRAINLIEST<br> -SEE ATTACHMENT-
yuradex [85]

ANSWER

(x - 5) ^{5}  =  {x}^{5}  - 25 {x}^{4} + 250 {x}^{3}   - 1250 {x}^{2} + 3125x- 3125

EXPLANATION

From the Pascal's triangle,

The coefficients are :

1, 5, 10,10, 5,1

Because of the negative sign, the expansion will alternate sign.

(x - y) ^{5}  =  {x}^{5}  - 5 {x}^{4} y + 10 {x}^{3}  {y}^{2}  - 10 {x}^{2}  {y}^{3}  + 5x {y}^{4}  -  {y}^{5}

We now put y=5 into the expansion to get,

(x - 5) ^{5}  =  {x}^{5}  - 5 {x}^{4} (5) + 10 {x}^{3} ( {5}^{2})  - 10 {x}^{2}  ({5})^{3}  + 5x( {5})^{4}  - {5}^{5}

(x - 5) ^{5}  =  {x}^{5}  - 25 {x}^{4} + 250 {x}^{3}   - 1250 {x}^{2} + 3125x- 3125

3 0
3 years ago
Read 2 more answers
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