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Temka [501]
3 years ago
11

What is the formula to calculate the surface area of a rectangular prism with a cube removed?

Mathematics
1 answer:
ch4aika [34]3 years ago
3 0
<span> 2ab + 2bc + 2ac the formula for the rectangular prism and i'm guessing you would find the answer to this than you would find your formula for the cube which is </span><span><span>6 a </span>2 and you would find that answer. 
</span>You would take your total for the rectangular prism answer and subtract the cube answer from it and you would probably get your answer. 
hope that helped?!
:)

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What is unknown number in proportion?
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Answer:

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Step-by-step explanation:

Multiply both sides by 4 to eliminate the fraction 1/4:

1      20

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x      2.4

Next, we cross-multiply.  This eliminates the fractions:

20x = 2.4

Dividing both sides by 20 results in an equation for x:  x = 2.4/20= 0.12

4 0
3 years ago
The first side of a triangle is 2 inches shorter than the second side. The third side is 5 inches longer than the second side. I
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Let the length of second side be x" ,

So,
Length of first side = 2" shorter than second = ( x - 2 )"
Length of third side = 5" longer than second = ( x + 5 )"




=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=×=




\text{Perimeter = sum of all sides  }



Given, perimeter = 33"




= > first side + second side + third side = 33"


= > ( x - 2 ) + x + ( x + 5 ) = 33

= > x - 2 + x + x + 5 = 33

= > 3x + 3 = 33

= > 3x = 30


= \:   >  x = \frac{30}{3}


= > x = 10








Hence, length of each side is

First side = ( x - 2 )" = ( 10 - 2 )" = 8 inches

Second side = x " = 10 inches

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

We are given a relation between the numbers of students in two different groups. That relation can be used to write an equation.

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If we consider M&M buyers to be 6 in a group, then the number of those groups is ...

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<h3>Groups who bought gum</h3>

Similarly, the number of groups who bought gum will be ...

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<h3>Equation</h3>

The problem statement tells us that for each group of one kind, there is a matching group of the other kind. That is, the numbers of groups are equal:

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