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jasenka [17]
2 years ago
10

The figure below shows circle with center O and regular hexagon ABCDEF constructed inscribed in a circle.Which of the following

steps will help prove that triangle FBD is equilateral?

Mathematics
2 answers:
Vikki [24]2 years ago
6 0

Answer:

As mentions in the explanation steps

Step-by-step explanation:

In the given figure hexagonal ABCDEF is a regular hexagonal, therefore each interior angles and sides of the hexagonal are same.

Now, the following steps are  helpful to prove that the triangle FBD is equilateral.

(1). Join the the three pints (pint F, pint B, pint D ) with the help of line segments and formed a triangle FBD.

(2). In ΔFAB, ΔBCD, ΔDEF two sides of each triangle and included angle are same( because two sides of each triangle and included angle must be the sides and interior angle of the given regular hexagon ABCDEF).  So ΔFAB, ΔBCD and  ΔDEF are congruence to each other by SAS postulate.

(3). By corresponding part of congruence triangle we say that line segment FB, line segment BD and line segment DF are same.

(4). Hence ΔFBD is an equilateral triangle, because all sides are same (from step -3).

mote1985 [20]2 years ago
4 0
I hope this helps you

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The given line passes through the points (0, ) and (2, 3). On a coordinate plane, a line goes through (0, negative 3) and (2, 3)
Kipish [7]

Answer:

y=\frac{x}{5}+\frac{12}{5}

Step-by-step explanation:

1) The Point-slope form equation is given in this form:

(x-x_{0})=m(y-y_{0})

2)Looking at the given graph, we can pick two points: (-5,-4) and (0,-3)

3) Before using the Point-slope form We have to find out the slope:

m=\frac{-4-(-3)}{0-(-5)} \Rightarrow m=\frac{-4+3}{0+5} \Rightarrow m=\frac{-1}{5}

4)Parallel lines share the same slope. The one that passes through (-2,2) is found by calculating its linear parameter "b":

y=\frac{x}{5}+b\Rightarrow 2=\frac{-2}{5}+b\\5*10=(-2+b)*5\Rightarrow 5b=12 \Rightarrow \frac{5b}{5} =\frac{12}{5} \Rightarrow b=\frac{12}{5}

Then, the answer is:

y=\frac{x}{5}+\frac{12}{5}

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2 years ago
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Which of the following is a correctly written algebraic equation?
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C. a-3x=0

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what are the two major advantages of experimental research over correlational studies? multiple select question. experiments are
Aloiza [94]

The experimental research has two key advantages over correlational studies.

1. The possibility of random assignment

2. Causal connections can be assumed.

<h3>What benefit does experimental research have over correlational research?</h3>

Correlational studies merely examine the data that already exists, whereas experimental studies give the researcher the opportunity to influence the study's factors. Researchers can make inferences about how changes in one variable affect changes in another through the use of experimental investigations.

The factors in a correlation study are out of the control of the researcher or research team. The researcher merely measures the information she discovers in the outside world. She can then determine whether changes in one are related to changes in the other, or if the two variables are correlated. In such a study, experimenters gather existing data and use statistical methods to examine it, such as economic statistics from governments. The findings of correlation studies can lead to hypotheses that can be verified through a more focused experimental one.

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1 year ago
Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)
Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

x^{2} +y^{2}+4x-1=0

Step-by-step explanation:

<u>Explanation:</u>-

<u>Step 1:</u>-

The equation of the circle having center and radius is

(x-h)^2+(y-k)^2=r^2

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

      (\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2}  )

    (-2,0)

therefore center (h,k) = (-2,0)

<u>Step 2:-</u>

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}

r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}

r=\sqrt{5}

<u>Step 3</u>:-

center (h,k) = (-2,0) and

radius r=\sqrt{5}

The standard form of circle equation

(x-h)^2+(y-k)^2=r^2

(x-(-2))^2+(y-0)^2=\sqrt{5} ^2

on simplification is

x^{2} +y^{2}+4 x-1=0

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