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Fiesta28 [93]
4 years ago
10

Simplify the expression. 27÷3+6 ⋅ 2 Enter your answers in the boxes.

Mathematics
1 answer:
BARSIC [14]4 years ago
8 0

First box is 9

Second box is 9, 12

Third box is 21

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1/6

Step-by-step explanation:

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3 years ago
Three polynomials are factored below, but some coefficients and constants are missing. All of the missing values of a, b, c, and
mariarad [96]

9514 1404 393

Answer:

  1. (a, b, c, d) = (1, -4, 1, -2)
  2. (a, b, c, d) = (1, -4, 1, 2)
  3. (a, b, c, d) = (1, -4, 2, 6)

Step-by-step explanation:

Once you remove the common factor from the terms, you are looking for factors of the remaining constant term that have a sum equal to the coefficient of the linear term. These factors are the constants in the binomial factors.

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1. 8 = (-4)(-2)   ⇒   x^2 -6x +8 = (x -4)(x -2)

  (a, b, c, d) = (1, -4, 1, -2)

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2. -8 = (-4)(+2)   ⇒   3x^3 -6x^2 -24x = 3x(x -4)(x +2)

  (a, b, c, d) = (1, -4, 1, 2)

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3. -12 = (-4)(3)   ⇒   2x^2 -2x -24 = 2(x -4)(x +3) = (x -4)(2x +6)

   (a, b, c, d) = (1, -4, 2, 6)  or  (2, -8, 1, 3)

3 0
3 years ago
Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!
LUCKY_DIMON [66]

Answer:

=8\sqrt{15}b^{\frac{7}{2}}

Step-by-step explanation:

\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}

=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}

=\sqrt{40}b^2\sqrt{24b^3}

\sqrt{24b^3}

=\sqrt{24}\sqrt{b^3}

=\sqrt{24}b^{\frac{3}{2}}

=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

\sqrt{2^3}

=2^{3\cdot \frac{1}{2}

=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}

2^{\frac{3}{2}+\frac{3}{2}}

=2^3

=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}

b^{\frac{3}{2}+2}

=b^{\frac{7}{2}}

=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}

=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}

=8\sqrt{15}b^{\frac{7}{2}}

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