We can rewrite the expression under the radical as

then taking the fourth root, we get
![\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cleft%28%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%29%5E4%7D%3D%5Cleft%7C%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%7C)
Why the absolute value? It's for the same reason that

since both
and
return the same number
, and
captures both possibilities. From here, we have

The absolute values disappear on all but the
term because all of
,
and
are positive, while
could potentially be negative. So we end up with

Answer:
- 150
Step-by-step explanation:
5×-30?-----) -150 is the answer
Answer: The value of y=9.
Hey there! :)
You have to find the area of all of them and add it together.
Formulas:
Area of a square: l · w
Area of a triangle: (b · h) ÷ 2
Square -
l = 3
w = 3
3 × 3 = 9
Triangle -
b = 3
h = 3
(3 × 3) ÷ 2
9 ÷ 2 = 4.5
There are 4 triangles
4.5 × 4 = 18
9 + 18 = 27
The surface area ⇒ 27 cm²