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Snowcat [4.5K]
4 years ago
14

A)How many moles of O2 are required for the complete combustion of 2.2 g of C3H8 to form CO2 and H2O?

Chemistry
1 answer:
Oksana_A [137]4 years ago
4 0
<span>A)How many moles of O2 are required for the complete combustion of 2.2 g of C3H8 to form CO2 and H2O?

C3H8 + 5O2 = 3CO2 + 4H2O

2.2 g C3H8 ( 1 mol / 44.11 mol ) ( 5 mol O2 / 1 mol C3H8) = 0.25 mol O2


b)A 65.25 g sample of CuSO4•5H2O (M = 249.7) is dissolved in enough water to make 0.800 L of solution. What volume of this solution must be diluted with water to make 1.00 L of 0.100 M CuSO4?

M1V1 = M2V2
[65.25 ( 1 / 249.7 )/ 0.800 L] (V1)= 0.100  (1.00 L)
V1 = 0.31 L or 310 mL </span>
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Suppose that 0.25 mole of gas C was added to the mixture without changing the total pressure of the mixture. How does the additi
Yanka [14]

Here we have to get the effect of addition of 0.25 moles of gas C on the mole fraction of gas A in a mixture of gas having constant pressure.

On addition of 0.25 moles of C gas, the mole fraction of gas A will be  \frac{moles of gas A}{moles of gas A + 0.25}.

The partial pressure of gas A can be written as P_{A} = x_{A}×P (where x_{A} is the mole fraction of gas A present in the mixture and P is the total pressure of the mixture.

The mole fraction of gas A in a mixture of gas A and C is = \frac{moles of gas A}{moles of gas A + moles of gas C} and \frac{moles of gas C}{moles of gas A + moles of gas C} respectively.

Thus on addition of 0.25 moles of C gas, the mole fraction of gas A will be  \frac{moles of gas A}{moles of gas A + 0.25}.

Which is different from the initial state.

4 0
3 years ago
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An endothermic solution process is described by which of the following?
Temka [501]

Answer:

a. ΔΗ > 0, solution feels cold

Explanation:

Hello,

In this case, endothermic process are those in which we can find that the products have more energy than the reactants, therefore energy is absorbed, for which the following equation:

\Delta H=\Delta H_{products}-\Delta H_{reactants}

Must be greater than 0 (positive) thereby, for a solution process we find that the solution feels cold, in such a way, answer is a. ΔΗ > 0, solution feels cold.

Regards.

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What do the repetitive patterns in a mineral form
siniylev [52]

Answer:

The repeating pattern of a mineral's particles form a solid called a <u>crystal</u>.

Explanation:

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Which of the following is true regarding the speed of earthquake waves?
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Surface waves arrive at a seismograph first because they are not impeded by rocks
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Lab: Applications of electromagnetic​
Pavlova-9 [17]

Answer:Not the same class but it will give u 100%

Explanation:

1. This experiment was to find how mass and speed effect KE. This is important because if you were in a situation where you needed something to go higher, you would know to add more or less of mass/speed.  

To test mass, we filled the bean bag with a certain amount of water, then dropped it. After, you recorded how high it made the bean bag go. The same with speed, but same amount in the bottle, just dropped from different heights.  

My hypothesis is when you have more mass, the KE will be greater. This is also the same with speed, if it is dropped from a higher place, the bean bag will launch farther than the last time.  

2. Data I collected from the lab was like my hypothesis explained. When the height of the bottle increased, it made the bean bag go higher than the last. And I tested 4 different masses, 0.125 kg, 0.250kg, 0.375kg and 0.500kg. Each time the bean bag went higher on a larger mass.  

A lot of times on the speed test, the bean bag would go higher than the bottle drop point, but not every time. Also, when it was dropped from the same height each time, some results varied quite a bit, like when it was dropped from 1.28 the results were 1.14 then 1.30 1.30. Mass on the other hand was all in the same number range, only once the numbers were a bit off from each other.  

3.  Some formulas I used were KE= ½ mv^2 and Ht v^2/2g. The first was to calculate the kinetic energy of an object, m=mass v=speed. Second was for finding out what height I needed to drop something to reach a certain speed, Ht=Height and g= Gravitational Acceleration of 9.8 m/s^2.  

I used these to figure out tables that showed relationships between different things like mass and KE or speed and height. The whole time I was doing the lab, my data was going up, when there was more mass/speed there were higher values in the table.  

This means that my hypothesis at the beginning was correct, more of m/s means KE will increase proportionally because they are all linear. I found it surprising when the bean bag height went over the water bottle drop mark.  

4.     To conclude, my hypothesis matched my data. The data values went up when more mass or speed was added. This means if I were in a situation where I needed more kinetic energy for something, I would know to increase mass or the speed of the object giving it energy.  

The reason that this hypothesis is correct is when you have more mass, you have more energy. So, when you drop let's say a baseball, it isn’t that heavy so it would only launch the bean bag so far. But a bowling ball is very heavy and has lots of energy when falling because of that, it would make the bean bag go very high.  

To make this experiment better, I would use a smoother material for the lever so energy wouldn’t be lost by friction from wood rubbing together. Also, maybe a scanner or video camera to more accurately record how far the bean bag went. All of these would help the lab get more precise results, maybe they could be used in a future lab.

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2 years ago
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