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vagabundo [1.1K]

3 years ago

11

Q2. How many molecules of CO2 are present in 0.20 mol of CO2? [Show your calculation)

1 answer:

Gnom [1K]3 years ago

4 0

Answer:

Explanation: Q2. How many molecules of CO2 are present in 0.20 mol of CO2? [Show your calculation)Q2. How many molecules of CO2 are present in 0.20 mol of CO2? [Show your calculation)Q2. How many molecules of CO2 are present in 0.20 mol of CO2? [Show your calculation)Q2. How many molecules of CO2 are present in 0.20 mol of CO2? [Show your calculation)Q2. How many molecules of CO2 are present in 0.20 mol of CO2? [Show your calculation)

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The law of conservation of matter states that matter can be neither created nor destroyed. Your friend shows you the following c

WITCHER [35]

Answer:

According to conservation of matter, there should be equal amounts of all elements on both the reactant and product side.

Reactant:

1 Ca

1 C

1 O

Product:

1 Ca

1 C

3 O

Therefore, your friend is right because the law of conservation of matter is not followed in this chemical equation.

Explanation:

6 0

3 years ago

Use the data given below to construct a Born-Haber cycle to determine the heat of formation of KCl. Δ H°(kJ) K(s) → K(g) 89 K(g)

AURORKA [14]

Explanation:

The net equation will be as follows.

$K(s) + Cl_{2}(g) \rightarrow KCl(s)$

So, we are required to find $\Delta H_{formation}$ for this reaction.

Therefore, steps involved for the above process are as follows.

Step 1: Convert K from solid state to gaseous state

$K(s) \rightarrow K(g)$ , $\Delta H_{1}$ = 89 kJ

Step 2: Ionization of gaseous K

$K(g) \rightarrow K^{+}(g) + e^{-}$ , $H_{2}$ = 418 KJ

Step 3: Dissociation of $Cl_{2}$ gas into chlorine atom .

$\frac{1}{2} Cl_{2}(g) \rightarrow Cl(g)$ , $\Delta H_{3} = \frac{244}{2}$ = 122 KJ

Step 4: Iozination of chlorine atom.

$Cl(g) + e^{-} \rightarro Cl^{-}(g)$ , $H_{4}$ = -349 KJ

Step 5: Add $K^{+}$ ion and $Cl^{-}$ ion formed above to get KCl .

$K^{+}(g) + Cl^{-}(g) \rightarrow KCl(s)$ , $H_{5}$ = -717 KJ

Now, using Born-Haber cycle, value of enthalpy of the formation is calculated as follows.

$\Delta H_{f} = \DeltaH_{1} + \Delta H_{2} + \Delta H_{3} + \Delta H_{4} + \Delta H_{5}$

= 89 + 418 + 122 - 349 - 717

= - 437 KJ/mol

Thus, we can conclude that the heat of formation of KCl is - 437 KJ/mol.

5 0

4 years ago

An iron atom has an atomic mass of 56. Its atomic number is 26. How many neutrons does the iron atom have?

Ghella [55]

Answer:

30

Explanation:

atomic mass = proton number + neutron number

proton number is also atomic number

8 0

3 years ago

Match each term to the best description.

ohaa [14]

Solution :

Term Best description

Eriochrome Black T EBT

Starting color, before titration Pale purple-pink color

Molecule that has a high affinity for metal ions Chelating agent

Ethylenediaminetetracetic acid EDTA

Color at the completion of titration Blue-gray color

3 0

3 years ago

How many moles of each element are in one mole of Sr(HCO,),? (3 points)

Mama L [17]

Answer: 1 mole of strontium, 2 moles of hydrogen, 2 moles of carbon, 6 moles of O

Explanation: i think i’m not sure

3 0

3 years ago