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vagabundo [1.1K]
3 years ago
11

Q2. How many molecules of CO2 are present in 0.20 mol of CO2? [Show your calculation)​

Chemistry
1 answer:
Gnom [1K]3 years ago
4 0

Answer:

Explanation: Q2. How many molecules of CO2 are present in 0.20 mol of CO2? [Show your calculation)​Q2. How many molecules of CO2 are present in 0.20 mol of CO2? [Show your calculation)​Q2. How many molecules of CO2 are present in 0.20 mol of CO2? [Show your calculation)​Q2. How many molecules of CO2 are present in 0.20 mol of CO2? [Show your calculation)​Q2. How many molecules of CO2 are present in 0.20 mol of CO2? [Show your calculation)​

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The law of conservation of matter states that matter can be neither created nor destroyed. Your friend shows you the following c
WITCHER [35]

Answer:

According to conservation of matter, there should be equal amounts of all elements on both the reactant and product side.

Reactant:

1 Ca

1 C

1 O

Product:

1 Ca

1 C

3 O

Therefore, your friend is right because the law of conservation of matter is not followed in this chemical equation.

Explanation:

6 0
3 years ago
Use the data given below to construct a Born-Haber cycle to determine the heat of formation of KCl. Δ H°(kJ) K(s) → K(g) 89 K(g)
AURORKA [14]

Explanation:

The net equation will be as follows.

          K(s) + Cl_{2}(g) \rightarrow KCl(s)

So, we are required to find \Delta H_{formation} for this reaction.

Therefore, steps involved for the above process are as follows.

Step 1:  Convert K from solid state to gaseous state

          K(s) \rightarrow K(g),    \Delta H_{1} = 89 kJ

Step 2:  Ionization of gaseous K

           K(g) \rightarrow K^{+}(g) + e^{-},    H_{2} = 418 KJ

Step 3:  Dissociation of Cl_{2} gas into chlorine atom .

            \frac{1}{2} Cl_{2}(g) \rightarrow Cl(g),   \Delta H_{3} = \frac{244}{2} = 122 KJ

Step 4: Iozination of chlorine atom.

              Cl(g) + e^{-} \rightarro Cl^{-}(g),      H_{4} = -349 KJ

Step 5:  Add K^{+} ion and Cl^{-} ion formed above to get KCl .

              K^{+}(g) + Cl^{-}(g) \rightarrow KCl(s),   H_{5} = -717 KJ

Now, using Born-Haber cycle, value of enthalpy of the formation is calculated as follows.

      \Delta H_{f} = \DeltaH_{1} + \Delta H_{2} + \Delta H_{3} + \Delta H_{4} + \Delta H_{5}

                  = 89 + 418 + 122 - 349 - 717

                  = - 437 KJ/mol

Thus, we can conclude that the heat of formation of KCl is - 437 KJ/mol.

5 0
4 years ago
An iron atom has an atomic mass of 56. Its atomic number is 26. How many neutrons does the iron atom have?
Ghella [55]

Answer:

30

Explanation:

atomic mass = proton number + neutron number

proton number is also atomic number

8 0
3 years ago
Match each term to the best description.
ohaa [14]

Solution :

  Term                                                                      Best description

Eriochrome Black T                                                          EBT

Starting color, before titration                               Pale purple-pink color

Molecule that has a high affinity for metal ions       Chelating agent

Ethylenediaminetetracetic acid                                    EDTA

Color at the completion of titration                           Blue-gray color    

3 0
3 years ago
How many moles of each element are in one mole of Sr(HCO,),? (3 points)
Mama L [17]

Answer: 1 mole of strontium, 2 moles of hydrogen, 2 moles of carbon, 6 moles of O

Explanation: i think i’m not sure

3 0
3 years ago
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