A bag of wheat 60kg find the height to which it is lifted so that its potential energy is 3000j
1 answer:
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Answer:
|A| = √(Ax)^2 + (Ay)^2
|A| = √(7.6)^2 + (-6.4)^2
|A| = √98.72
|A| = 9.9
Answer:
|A| = √(Ax)^2 + (Ay)^2
|A| = √(7.6)^2 + (-6.4)^2
|A| = √98.72
|A| = 9.9