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Luba_88 [7]
3 years ago
12

If ∠Q = 47°,

Mathematics
2 answers:
yuradex [85]3 years ago
8 0
∠Q = ∠R = 47°

answer
<span>∠R

------------------------</span>
olchik [2.2K]3 years ago
5 0

Answer:

Option C is correct

\angle R

Step-by-step explanation:

Definition:

Angle subtended by the chord on the same segment are equal.

From the given figure:

\angle Q =47^{\circ}

Draw a line that join S and T.

Here, ST line segment represents Chord.

\angle R and \angle Q subtended by the chord ST on the same segment

then by above definition:

\angle R = \angle Q = 47^{\circ}

Therefore, the angle R measures 47 degrees.

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Find sin0, cos0, tan0
djverab [1.8K]

Answer:

sin(θ) = 12/13, cos(θ) = 5/13, tan(θ) = 12/5

Step-by-step explanation:

We need to find sine, cosine, and tangent of theta for this triangle.

First, define the different trigonometric functions:

- sine is opposite side to the angle divided by the hypotenuse (longest side not adjacent to the 90 degree angle)

- cosine is the adjacent side next to the angle divided by the hypotenuse

- tangent is the opposite side to the angle divided by the adjacent side

Now, look at theta (θ):

- the opposite side is marked 12

- the adjacent side is marked 5

- the hypotenuse is marked 13

So:

- sin(θ) = opposite / hypotenuse = 12/13

- cos(θ) = adjacent / hypotenuse = 5/13

- tan(θ) = opposite / adjacent = 12/5

Thus the answers are: sin(θ) = 12/13, cos(θ) = 5/13, tan(θ) = 12/5.

6 0
3 years ago
Read 2 more answers
Who can answer this<br> (WITH AN EXPLANATION)<br> will mark brainlest
stepan [7]

Answer:

Factors: (x²y+6)(y²-11)

<h2 />

Step-by-step explanation:

Here's the original equation.

x²y³ - 11x²y + 6y² - 66

Let's separate it into two groups to make it easier.

(x²y³ - 11x²y) + (6y² - 66)

Let's take a look at (x²y³ - 11x²y) first. Do we notice anything that can be removed from the parentheses?

Yes, x²y can be taken from both polynomials to simplify the contents of the parentheses.

Both polynomials have x² and both have at least one y. Combine that to get x²y. That means that within the parentheses y² and - 11 will be left.

So  (x²y³ - 11x²y) becomes x²y (y²-11)

This works because if we multiply x²y * (y² - 11) we get (x²y³ - 11x²)

Let's apply this same idea to (6y² - 66).

6 is the only thing in common between the two polynomials.

If we follow the same steps we get 6 (y²-11).

Notice how when we simplified both groups they each had something on the outside and (y² - 11) in the parentheses?

So lets combine the things that were on the outside of both (y² - 11).

What was on the outside of each? x²y was on the outside for the first one, and 6 for the outside of the second one.

This means that if we combine everything and simplify, the factors we have are (x²y+6)(y²-11).

If you want to confirm, work your way backwards using the distributive property. You'll find that when you multiply (x²y+6) * (y² -11) you'll get = x²y³ - 11x²y + 6y² - 66. That was the original equation, so we know that these are the factors.

Hope that helps!

8 0
3 years ago
Pls answer both thank usm
KonstantinChe [14]
1) 1.75

How many balloons she blows up
7 0
2 years ago
Find an order pair (x, y) that is a solution to the equation <br> -x+6y=3
Lelu [443]
One solution is the y intercept (0,1/2)
3 0
3 years ago
Please help me 10 points
Oksana_A [137]
7\dfrac{2}{9}-3\dfrac{5}{6}=7\dfrac{2\cdot2}{9\cdot2}-3\dfrac{5\cdot3}{6\cdot3}=7\dfrac{4}{18}-3\dfrac{15}{18}\\\\=6\dfrac{22}{18}-3\dfrac{15}{18}=3\dfrac{7}{18}
7 0
3 years ago
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