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3 years ago

7

Henry incorrectly said the rate 1/5/2/15 can be written as the unit rate 1/75 gallon per minute. What is correct unit rate? What

was Henrey's likely error?

1 answer:

Gwar [14]3 years ago

8 0

Answer:d

Step-by-step explanation:

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Darius lives in Ohio and pays 5.5% in sales tax. If he just bought a sweatshirt that cost $24, what was the total amount he paid

ollegr [7]

In this question, we are required to find the total amount he paid to buy the shirt.

It is given that sales tax is 5.5 % over the amount paid.

The cost price of the shirt = $ 24.

The total amount will be = Cost price + 5.5 % of Cost price

Or

Total amount paid = $ 24 × 1.055 (i.e. 100 % + 5.5 %)

Total amount = $ 24 + (5.5 % × $ 24)

Total amount paid = $ 24 + $ 1.32 = $ 25.32

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3 years ago

Read 2 more answers

The chess club members bought six tickets to a tournament for $15. how much would they have paid if all nine members wanted to g

ElenaW [278]

15/6=2.5
2.5x9=22.5
$22.50 is your answer

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3 years ago

What is 4/7 times 5/p

Phantasy [73]

Answer:

p = 35/4 = 8.750

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

4/7-(5/p)=0

6 0

3 years ago

(5x - 2y)^3<br> Expand using Bionomial Theorum. Show steps, please.

tatyana61 [14]

Answer:

125x³ − 150x²y + 60xy² − 8y³

Step-by-step explanation:

(5x − 2y)³

₃C₀ (5x)³ (-2y)⁰ + ₃C₁ (5x)² (-2y)¹ + ₃C₂ (5x)¹ (-2y)² + ₃C₃ (5x)⁰ (-2y)³

(1) (125x³) (1) + (3) (25x²) (-2y) + (3) (5x) (4y²) + (1) (1) (-8y³)

125x³ − 150x²y + 60xy² − 8y³

7 0

3 years ago

A new screening test for Lyme disease is developed for use in the general population. The sensitivity and specificity of the new

Anit [1.1K]

Answer:

predictive value of a positive test = 18.18%

predictive value of a negative test = 94.03%

Step-by-step explanation:

Sensitivity = 60% = 0.6

Specificity = 70% = 0.7

Let True Positive = TP

True Negative = TN

False Negative = FN

$Sensitivity = \frac{TP}{TP + FN} \\0.6 = \frac{TP}{TP + FN} \\0.6TP + 0.6FN = TP\\0.4TP = 0.6FN\\TP = 1.5 FN$

$Specificity = \frac{TN}{TN + FP} \\0.7 = \frac{TN}{TN + FP} \\0.7TN + 0.7FP = TN\\0.7FP = 0.3 TN\\TN = 7/3 FP$

Prevalence = 10% = 0.1

Three hundred people are screened, $T_{total} = 300$

Total number of people having the disease, $T_{disease} = ?$

$Prevalence = \frac{T_{disease} }{T_{total} } \\0.1 = \frac{T_{disease} }{300 }\\T_{disease} = 30$

$T_{disease} = TP + FN\\30 = TP + FN$

But TP = 1.5 FN

30 = 1.5 FN + FN

30 = 2.5 FN

FN = 30/2.5

FN = 12

TP = 1.5 FN = 1.5 * 12

TP = 18

$FP + TN = T_{total} - T_{disease} \\FP + TN = 300 - 30\\FP + TN = 270\\FP + \frac{7}{3} FP = 270\\\frac{10}{3} FP = 270\\FP = 27 * 3\\FP = 81$

81 + TN = 270

TN = 189

To calculate the Predictive value of positive test (PPT)

$PPT = \frac{TP}{TP + FP} * 100\\PPT = \frac{18}{18+81} * 100\\PPT = \frac{18}{99} * 100\\PPT = 18.18 \%$

To calculate the Predictive value of negative test (PNT)

$PPT = \frac{TN}{FN + TN} * 100\\PPT = \frac{189}{189+12} * 100\\PPT = \frac{189}{201} * 100\\PPT = 94.03 \%$

7 0

3 years ago