0.4 is the answer to this
Answer:
Correct option:
(B) <em>H₀</em>: <em>μ</em> = 2.40 vs. <em>Hₐ</em>: <em>μ</em> ≠ 2.40.
Step-by-step explanation:
The registrar of particular university in 1975 plans to look at records of students graduating last year to see if the mean GPA has changed from 2.40.
The registrar can use a single mean test to determine whether the mean has changed or not.
The hypothesis can be described as:
<em>H₀</em>: The mean GPA is 2.40, i.e. <em>μ</em> = 2.40.
<em>Hₐ</em>: The mean GPA is different from 2.40, i.e. <em>μ</em> ≠ 2.40.
To perform the test the registrar can either use a <em>z</em>-distribution or a <em>t</em>-distribution.
If the data provided gives some insight about the population standard deviation and the sample selected is quite large then the <em>z</em>-distribution can be used.
Otherwise it is wiser to use a <em>t</em>-distribution.
The decision rule is:
If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.
Thus, the correct option is (B).
First, set up a proportion. 10.3% is the percentage of students who cancelled, but the question is asking for the students who are attending, so let’s use 89.7% to make it easier. The proportion would be x over 58 is equal to 89.7% over 100%. Multiply 58 by 89.7, giving you 5,202.6. Next, take 5,202.6 and divide it by 100. This should give you 52. 026, but it’s best to round this to 52. 52 students actually attend the art class, making this your final answer.
