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3 years ago

Evaluate a/b for a = -6 and b = -2

Mathematics

2 answers:

kati45 [8]3 years ago

7 0

Answer:

The Answer is 3 !

Step-by-step explanation:

Your welcome buddy

Westkost [7]3 years ago

5 0

Answer:

if solved correctly, you'll get 3 as your answer

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What is the result of subtracting the second equation from the first?

gtnhenbr [62]

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3 years ago

What is the value of this expression? 4/15+3/5−2/3 Quick

VMariaS [17]

Answer:

I think that would be 1/5

Explanation:

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2 years ago

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Answer:

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3 years ago

Which function is equivalent to y = 2(x – 4)^2 + 8?

Flura [38]

Answer:

B: y = 2x² - 16x + 40

Step-by-step explanation:

You can find this simply by expanding the given function:

y = 2(x - 4)² + 8

y = 2(x² - 8x + 16) + 8

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y = 2x² - 16x + 40

8 0

2 years ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0

3 years ago