What is the GCF of 12 and 48

*** -6 Simplify 21v6 ÷ (-7v-6) O 0 -3y¹2 -3 12 0 -3 DONE 0 0

-Dominant- [34]

Answer:

-3

Step-by-step explanation:

$\frac{ 21y {}^{ - 6} }{ - 7y {}^{ - 6} } \\ - 3y {}^{ - 6 - ( - 6)} \\ - 3y {}^{ - 6 + 6} \\ - 3y {}^{0} \\ - 3(1) \\ - 3$

3 0

2 years ago

Is -2.74 a rational number?

Zinaida [17]

Yes, in mathematics, a rational number is any numberthat can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q.

5 0

3 years ago

Read 2 more answers

Segment BD is an altitude of triangle ABC. Find the area of the triangle. Triangle ABC with altitude BD is shown. Point A is at

pogonyaev

Where's the "triangle with alt. BD?" This problem can be solved without the diagram, but the solution would be easier with it.

BD is the altitude. Find the length of BD by finding the dist. between (-1,4) and (2,4); it is 2-(-1), or 3. |BD| = 3.

I've graphed the triangle myself and have found that the "base" of the triangle is the vertical line thru (2,1) and (2,6); its length is 6-1, or 5.

Thus, the area of this triangle is A = (b)(h) / 2, or A = (5)(3) / 2 = 10/3 square inches.

7 0

3 years ago

Read 2 more answers

(-9) + (-4) =

Gwar [14]

$\\ \bull\sf\longmapsto -9+(-4)=-9-4=-13$

$\\ \bull\sf\longmapsto +3-(-5)=3+5=8$

$\\ \bull\sf\longmapsto 2\times 2=4$

$\\ \bull\sf\longmapsto 36+4=40$

$\\ \bull\sf\longmapsto 5\times 7=35$

$\\ \bull\sf\longmapsto 8(9)=72$

$\\ \bull\sf\longmapsto -4+(-2)=-4-2=-6$

$\\ \bull\sf\longmapsto 3-(-6)=3+6=9$

$\\ \bull\sf\longmapsto -6(-3)=18$

$\\ \bull\sf\longmapsto -4+(-4)=-4-4=-8$

$\\ \bull\sf\longmapsto 5(7)=35$

$\\ \bull\sf\longmapsto 4-(-5)=4+5=9$

$\\ \bull\sf\longmapsto 4-3=1$

$\\ \bull\sf\longmapsto 10+5=15$

$\\ \bull\sf\longmapsto 3(8)=24$

7 0

3 years ago

Need this really quick plz

Oduvanchick [21]

Answer:

Let

x=sin-¹u

Sinx=u

let y=tan-¹v

tany=v

Substituting

Sin[x + y]

Applying the sine expansion

Sinxcosy + CosxSiny

Recall x =Sin-¹u

y=tan-¹v

Sin(Sin-¹u)Cos(tan-¹v) +Cos(sin-¹u)Sin(tan-¹v)

Now at this point

Here's what you do

For the first expression

Sin(Sin-¹u)

Let's simplify this

Let P = Sin-¹u

Taking sine of both sides

SinP=u

Draw a Right angled angle for this

Since Sine from SOHCAHTOA is OPP/HYP

Where P is the angle and u is the opposite and 1 is the hypotenuse since u is the same as u/1

substituting Sin-¹u = P

You have

Sin(Sin-¹u) = SinP

and from the triangle you drew

SinP = u

Taking the second express

Cos(tan-¹v)

Let Q=Tan-¹v

taking tan of both sides

tanQ=v

Draw a right angled triangle for this too

Since Tan from SOHCAHTOA is OPP/ADJ

Find the Hypotenuse cos you'll need it

Now Let's do the substitution again

We first said tan-¹v = Q

When we substitute it in Cos(tan-¹v)

We have CosQ

Cos Q from the second right angle triangle you drew is 1/√1+v²

Because CAH is adj/Hyp

So

the first part of the original Express

Which is

Sin(Sin-¹u)Cos(tan-¹v) is now simplified to

u(1/√1+v²).

Let's Move to the second part of the Original Expression

Cos(Sin-¹u)Sin(tan-¹v)

From our first solution

We said Sin-¹u= P

So replacing it here

we have Cos(sin-¹u) = CosP

let's leave the second one for now which is sin(tan-1v) We'll deal with this after the first

so Cos(Sin-¹u) = CosP

we can still use our first Right angle triangle for this because the angle was P.

so Cos P from that triangle will be

CosP= √1-u²

Now onto the next

Sin(tan-¹v)

From the Second solution of the first we did

we said let Tan-¹v =Q

Substituting this

we have

Sin(tan-¹v) = SinQ

using the second Right angle triangle because its angle is Q

We have

SinQ= v/√1+v²

Answer for second phase Which is

Cos(sin-¹u)Sin(tan-¹v) = √1-u²(v/√1+v²)

We're done

compiling our answers

The answer to

Sin(Sin-¹u - tan-¹v) = u(1/√1+v²) + [(√1-u²)(v/√1+v²)]

You can still choose to factor out 1/√1+v² since it appears on both sides

8 0

2 years ago

What is the GCF of 12 and 48​

What is the GCF of 12 and 48