The dimensions be of any advertisement that wants to fill the longest side of the shape is of 2m and 1 m and 0.75 m
According to the statement
we have given that the Triangular prism of size 0.75 m, 1m and length of 2m.
And we have to find the by which size of advertisement board need to fill the longest side of the shape.
A triangular prism is a three-sided prism; it is a polyhedron made of a triangular base, a translated copy, and 3 faces joining corresponding sides.
So, for this purpose,
we know that the longest side of triangular prism is 2m and we have to cover it with the advertising board.
Obviously the length of the advertising board is of 2m to cover the longest side of the shape.
So, The dimensions be of any advertisement that wants to fill the longest side of the shape is of 2m and 1 m and 0.75 m
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Amount of tax would be: 6.95*20/100 = 139/100 = 1.39
So, the amount of 20% tax on $6.95 lunch would be $1.39
Answer:
(b) -61/16 | -15/4
Step-by-step explanation:
We assume you're using a binary search successive approximation technique that starts with an interval and cuts it in half with each iteration. The final approximation of the solution to the equation will be the midpoint of the interval after it has been cut in half 3 times.
The graph shows the intersection point of the curves lies between x = -4 and x = -3.
If we define h(x) = f(x) -g(x), then our first iteration will evaluate h(-7/2) and determine which end of the interval gets replaced. The attachment shows us that the sign of h(-7/2) is the same as the sign of h(-3), so -7/2 replaces -3 and the interval after the first iteration is [-4, -7/2].
The midpoint of this interval is -15/4. The sign of h(-15/4) is the same as the sign of h(-7/2), so the interval after the second iteration is [-4, -15/4].
The midpoint of this interval is -31/8. The sign of h(-31/8) is the same as the sign of h(-4), so the interval containing the solution after the third iteration is [-31/8, -15/4]. The approximate solution value after 3 iterations is (-31/8 -15/4)/2 = -61/16.
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