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MatroZZZ [7]
3 years ago
5

If a triangle has angles that fit the ratio 4:3:2, what would be the measure of each of the angles?

Mathematics
1 answer:
Harman [31]3 years ago
4 0

Answer:

80,60,40

Step-by-step explanation:

The three angles of a triangle add to 180

Multiply the ratio by x

The angles are 4x, 3x, 2x

Add them together

4x+3x+2x = 180

Add like terms

9x = 180

Divide by 9

9x/9 =180/9

x = 20

The angles are 4x = 4(20) = 80

                          3x= 3(20) = 60

                           2x= 2(20) = 40

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Tracy needs to find the length and width of the equiptment storage room where she works. the room is 2 meters long than it is wi
ElenaW [278]
Rectangle:
P = 2 (L+W) but length is 2 meters longer than wide
then L = W + 2, So
P = 2 (L + W)
24 = 2(W+2+W)
24 = 2 (2 + 2W)
24 = 4 + 4W
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Double check
24 = 2*(5+7) = 2 *12 = 24
4 0
3 years ago
Read 2 more answers
Please help and thank you
vladimir2022 [97]

Answer: A & D

Explanation: When you multiply 15 and 4 and add that to 20 and 2 it would be 100. When you multiply 25 and 4 and add that to 25 and 2 it would be 150. Hope this helps :).

7 0
3 years ago
The number of defects in the first five cars to come through a new production line are 9, 7, 10, 4, and 6, respectively. If the
garri49 [273]

Answer:

D. I and III only

Step-by-step explanation:

Number of first fie defects are given as 9,7,10,4 and 6.

First we have to arrange the above data in ascending order which is 4,6,7,9,10

  • Now if we consider the defect in sixth car to be 3 then our data will look like:    3,4,6,7,9,10

So the mean of above data would be \frac{3+4+6+7+9+10}{6} = 6.5

and Median of the above data would be = \frac{3^{rd} obs + 4^{th}  obs}{2} = \frac{6+7}{2} = 6.5

Hence mean and median number of defects are same if the sixth car has 3 defects.

  • Now if we consider the defect in sixth car to be 12 then our data will look like:    4,6,7,9,10,12

So the mean of above data would be \frac{4+6+7+9+10+12}{6} = 8

and Median of the above data would be = \frac{3^{rd} obs + 4^{th}  obs}{2} = \frac{7+9}{2} = 8

Hence mean and median number of defects are same if the sixth car has 12 defects.

  • But Now if we consider the defect in sixth car to be 7 then our data will look like:    4,6,7,7,9,10        

So the mean of above data would be \frac{4+6+7+7+9+10}{6} = 7.167    

and Median of the above data would be =  \frac{3^{rd} obs + 4^{th}  obs}{2} = 7

   Hence mean and median number of defects are not same if the sixth car has 7 defects.      

Therefore option D is correct.                                                                                  

8 0
3 years ago
Factor the equation.​
goblinko [34]

Answer:

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Step-by-step explanation:

Reorder terms.

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The PDF of the maximum
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Answer:

distinctly over here I think so

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