Question

In a basketball tournament, Team A scored 5 fewer than twice as many points as Team B. Team C scored 80 more points than Team B. The combined score for all three teams was 983 points. Write an equation to represent this scenario using the variable b to represent Team B’s total points.

Answer 1

Answer:

Team A= 2b-5

Team B= b

Team C= b+80

The equation representing this scenario is (2b-5)+ b + (b+80)= 983

Step-by-step explanation:

Answer 2

Let us assume number of points scored by Team B = b points.

Number of points scored by Team A 5 fewer than twice as many points as Team B, that is "5 less than 2b" = (2b-5) points .

Team C scored 80 more points than Team B, that is " 80 more than b" = (b+80) points.

Total number of points scored by all teams = 983 points.

Therefore, we can setup an equation:

(2b-5) + b + (b+80) = 983.

Therefore, an equation to represent this scenario using the variable b to represent Team B’s total points is (2b-5) + b + (b+80) = 983.