<span>A parallelogram is a quadrilateral whose opposite sides are parallel. ABCD is a parallelogram; AB II CD and AC II BD
Theorem: </span><span>opposite angles of a parallelogram are congruent
Given: Parallelogram PQRS
Prove: </span>∠CAB = ∠BDC and ∠ABD= ∠DCA
Refer to the attached picture to follow.
Create an extended line beyond and name it as point E and point F.
Proof:
∠CDB = ∠EBD - alternate interior angle
∠EBD = ∠CAB - corresponding angle
This makes ∠CDB congruent to ∠CAB.
∠ACD = ∠FAC - alternate interior angle
∠FAC = ∠ABD - corresponding angle
This makes ∠ACD congruent to ∠ABD
Proving that ∠CAB = ∠BDC and ∠ABD= ∠DCA or ∠CAB = ∠CDB and ∠ABD = ∠ACD
Right cylinderSolve for volumeV≈1005.31cm³<span><span><span>rRadiuscm</span><span>hHeightcm</span></span></span>
Given x^2-5x+c=7, the constant term c will be obtained using the formula:
c=(-b/2a)²
given that a=1 and b=-5 then plugging the values we shall have:
c=(-(-5)/2*1)²
c=(5/2)²
c=25/4
Answer: the constant is 25/4
Answer:
C = 6y + 35
Step-by-step explanation:
cost = cost for number of classes + monthly fee
C = 6y + 35