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rosijanka [135]
3 years ago
13

Please help ?!!! Solve the three equations in the table using any method of your choice. List the method you used.

Mathematics
2 answers:
Sav [38]3 years ago
4 0

Please Refer to the screenshot. Hope this helps!

KatRina [158]3 years ago
3 0

Step-by-step explanation:

x =  \frac{ - b \frac{ + }{ - }  \sqrt{ {b}^{2} - 4ac } }{2a}

The quadratic formula is honestly the most straightforward way of solving here.

Your other options are completing the square (which is the same thing as the quadratic formula but it's good to know that method if you have to take Integral Calculus at some point) or maybe factoring by grouping if it's appropriate. But the quadratic formula will work for you in all three equations:

1) a=1, b=0, c=8

This reduces pretty quickly into x=8i,-8i due to the negative under the radical. (Actually we didn't even really need the formula here.)

2) a=-9, b=4, c=-10

This reduces into x=(-4+i√(344))/-18, (-4-i√(344))/-18 and doesn't go any further because 344 isn't a perfect square.

3) a=1, b=8, c=17

This reduces to x=(-4+i), (-4-i)

So those are the answers for each.

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3 years ago
Which statement describes the decimal equivalent of 114?
lana [24]

Answer:

C. The decimal terminates after 2 decimal places.

Step-by-step explanation:

If we move twice to the right, we will see that it will now see 1.14. I will send you a picture.

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8 0
2 years ago
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Please solve, -8-2(7r+1)=-94​
skelet666 [1.2K]

Answer:

r = 6

Step-by-step explanation:

Hello!

-8 - 2(7r + 1) = -94

Add 8 to both sides

-2(7r + 1) = -86

Divide both sides by -2

7r + 1 = 43

Subtract 1 from both sides

7r = 42

Divide both sides by 7

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Hope this Helps

4 0
3 years ago
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1.Encuentra la ecuación de la circunferencia que tiene como ecuación ordinaria (x-4)² + (y+5)²= 25 2- encuentra la ecuación gene
rodikova [14]

Responder:

1) x² + y²-8x + 10y + 16 = 0

2) x² + y² + x + 18y + 33 = 0

Explicación paso a paso:

A partir de la pregunta, debemos expresar la ecuación en la forma estándar de un círculo expresado como;

x² + y² + 2gx + 2fy + c = 0 donde;

(-g, -f) es el centro.

1) Para la ecuación (x-4) ² + (y + 5) ² = 25

Expande el paréntesis;

(x-4) ² + (y + 5) ² = 25

x²-8x + 16 + y² + 10x + 25 = 25

x²-8x + 16 + y² + 10y + 25-25 = 0

Recopile términos similares;

x² + y²-8x + 10y + 16 + 0 = 0

<em>x² + y²-8x + 10y + 16 = 0 </em>

<em>Por lo tanto, la ecuación requerida es x² + y²-8x + 10y + 16 = 0 </em>

<em> </em>

2) Para la expresión (x + 1) ² + (y + 9) ² = 49

x² + x + 1 + y² + 18y + 81 = 49

x² + x + 1 + y² + 18y + 81-49 = 0

Recopile términos similares;

x² + y² + x + 18y + 82-49 = 0

<em>x² + y² + x + 18y + 33 = 0 </em>

<em>Por tanto, la ecuación requerida es x² + y² + x + 18y + 33 = 0</em>

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Step-by-step explanation:

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