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Bogdan [553]
3 years ago
11

a train starting from rest moving with uniform acceleration attains a speed of 36 km/hr in 10 seconds. Find its acceleration​

Physics
1 answer:
Savatey [412]3 years ago
8 0

Answer:

\boxed{\sf Acceleration \ of \ train = 1 \ m/s^{2}}

Given:

Initial speed (u) = 0 km/hr = 0 m/s

Final speed (v) = 36 km/hr

Time taken (t) = 10 sec

To Find:

Acceleration (a) of the train

Explanation:

\sf 1 \ km/hr = \frac{5}{18} \ m/s \\ \therefore \\ \sf 36 \ km/hr = 36 \times \frac{5}{18} \ m/s \\  \\  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = 2 \times  \cancel{18} \times  \frac{5}{ \cancel{18}}  \ m/s \\  \\  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \: = 2 \times 5 \ m/s \\  \\  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 10  \ m/s

So,

Final speed (v) = 10 m/s

\sf From \ equation \ of \ motion: \\ \sf \implies \bold{v = u + at} \\ \\ \sf Substituting \ value \ of \ v, \ u \ and \ t: \\ \sf \implies 10 = 0 + a(10) \\ \sf \implies 10 = a(10) \\ \sf \implies a \times 10 = 10 \\ \\ \sf Dividing \ both \ sides \ by \ 10: \\ \sf \implies \frac{a \times 10}{\boxed{\sf 10}} = \frac{10}{\boxed{\sf 10}} \\ \\ \sf \frac{\cancel{10}}{\cancel{10}} = 1: \\ \sf \implies a = 1 \:  m/s^2

Acceleration of train = 1 m/s²

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