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ivolga24 [154]
3 years ago
6

Okno okrętu podwodnego ma powierzchnię 0,3 m2 i znajduje się na głębokości, na której ciśnienie wywierane przez słup wody wynosi

500 kPa. Dokończ zdanie. Wartość siły parcia wody na okno wynosi.
Physics
1 answer:
OLEGan [10]3 years ago
4 0

Answer:

The value of the water pressure force on the window is 150,000 N.

Wartość siły nacisku wody na okno wynosi 150000 N.

Explanation:

English Translation

The submarine window has an area of ​​0.3 m2 and is located at a depth at which the pressure exerted by the water column is 500 kPa. Finish the sentence. The value of the water pressure force on the window is.

Solution.

Pressure exerted by a force on a surface area perpendicular to the line of action of that force is given by the formula

P = (F/A)

where F = applied force, in this case, water pressure force on the window = ?

A = Area upon which the force is acting = Area of the window = 0.3 m²

P = 500 kPa = 500,000 Pa

500,000 = (F/0.3)

F = 500,000 × 0.3 = 150,000 N

In Polish/Po Polsku

Ciśnienie wywierane przez siłę na pole powierzchni prostopadłe do linii działania tej siły jest określone wzorem

P = (F / A)

gdzie F = przyłożona siła, w tym przypadku siła nacisku wody na okno =?

A = Obszar, na który działa siła = Powierzchnia okna = 0,3 m²

P = 500 kPa = 500000 Pa

500,000 = (F/0.3)

F = 500,000 × 0.3 = 150,000 N

Hope this Helps!!!

Mam nadzieję że to pomoże!!!

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3 years ago
Rain drops fall on a tile surface at a density of 4638 drops/ft2. There are 17 tiles/ft2. How many drops fall on each tile? Answ
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Explanation:

Given that the Rain drops fall on a tile surface at a density of 4638 drops/ft2. There are 17 tiles/ft2. How many drops fall on each tile?

Tiles/ft^2 × drop/tiles = drop/ft^2

Tiles will cancel out. Leaving the answer to be drop/ ft^2

Substitutes all the magnitude of the above units.

17 × drop/tiles = 4638

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Drop/tiles = 272.82

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The S-strain Pneumococcus bacteria had a smooth surface, because ____________________.
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M84, M87, and NGC 4258 all have accretion disks around their central black holes for which the rotational velocities have been m
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Answer:

<u>For M84:</u>

M = 590.7 * 10³⁶ kg

<u>For M87:</u>

M = 2307.46 * 10³⁶ kg

Explanation:

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The equation of the orbit speed can be used to calculate the doppler velocity:

v = \sqrt{\frac{GM}{r} }

making m the subject of the formula in the equation above to calculate the mass of the black hole:

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r = 8 pc = 8 * 3.08 * 10¹⁶

r = 24.64 * 10¹⁶ m

v = 400 km/s = 4 * 10⁵ m/s

G = 6.674 * 10⁻¹¹ m³/kgs²

Substituting these values into equation (1)

M = \frac{( 4*10^{5}) ^{2} *24.64* 10^{16} }{6.674 * 10^{-11} }

M = 590.7 * 10³⁶ kg

<u>For M87:</u>

r = 20 pc = 20 * 3.08 * 10¹⁶

r = 61.6* 10¹⁶ m

v = 500 km/s = 5 * 10⁵ m/s

G = 6.674 * 10⁻¹¹ m³/kgs²

Substituting these values into equation (1)

M = \frac{( 5*10^{5}) ^{2} *61.6* 10^{16} }{6.674 * 10^{-11} }

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3 0
3 years ago
Tarik winds a small paper tube uniformly with 183 turns 183 turns of thin wire to form a solenoid. The tube's diameter is 9.49 m
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<h2>Answer:</h2>

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<h2>Explanation:</h2>

The inductance (L) of a coil wire (e.g solenoid) is given by;

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l = the length of the solenoid

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μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²

<em>From the question;</em>

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<em>But;</em>

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A = 3.142 x 0.00949² / 4

A = 7.1 x 10⁻⁵m²

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6 0
3 years ago
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