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3 years ago

What equation do we use to solve?

Physics

1 answer:

aev [14]3 years ago

4 0

V(y) is the same in all cases so time taken for all cannonballs to go up and down is the same.

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A muon has a rest mass energy of 105.7 MeV, and it decays into an electron and a massless particle. If all the lost mass is conv

sergeinik [125]

Answer:

The electron’s velocity is 0.9999 c m/s.

Explanation:

Given that,

Rest mass energy of muon = 105.7 MeV

We know the rest mass of electron = 0.511 Mev

We need to calculate the value of γ

Using formula of energy

$K_{rel}=(\gamma-1)mc^2$

$\dfrac{K_{rel}}{mc^2}=\gamma-1$

Put the value into the formula

$\gamma=\dfrac{105.7}{0.511}+1$

$\gamma=208$

We need to calculate the electron’s velocity

Using formula of velocity

$\gamma=\dfrac{1}{\sqrt{1-(\dfrac{v}{c})^2}}$

$\gamma^2=\dfrac{1}{1-\dfrac{v^2}{c^2}}$

$\gamma^2-\gamma^2\times\dfrac{v^2}{c^2}=1$

$v^2=\dfrac{1-\gamma^2}{-\gamma^2}\times c^2$

Put the value into the formula

$v^2=\dfrac{1-(208)^2}{-208^2}\times c^2$

$v=c\sqrt{\dfrac{1-(208)^2}{-208^2}}$

$v=0.9999 c\ m/s$

Hence, The electron’s velocity is 0.9999 c m/s.

6 0

3 years ago

A 243 mL cup of whole milk contains about 45 mg of cholesterol. Express the cholesterol concentration of the milk in kilograms p

timama [110]

Answer: $0.1851 \frac{kg}{m^{3}}$

Explanation:

We have this concentration in units of $mg/ml$ :

$\frac{45 mg}{243 ml}$

And we need to express it in $kg/m^{3}$ , knowing:

$1 ml= 1 cm^{3}$

$1 m^{3}= (100 cm) ^{3}$

$1g = 1000 mg$

$1 kg = 1000 g$

Hence:

$\frac{45 mg}{243 cm^{3}} \frac{1 g}{1000 mg} \frac{1 kg}{1000 g} \frac{(100 cm) ^{3}}{1 m^{3}}=0.1851 \frac{kg}{m^{3}}$

5 0

3 years ago

A truck is moving at 25.0 m/s and sees a barrier in the road 100 m ahead. The truck can decelerate at 4 m/s2. Will the truck hit

Nimfa-mama [501]

Answer:

No, the truck will not cross the barrier.

The closeness of the truck to the barrier is of 21.875 m

Solution:

As per the question:

Velocity of the truck, v = 25.0 m/s

Acceleration of the truck, a = - 4 $m/s^{2}$

Now,

Since, the barrier at a distance of 100 m. Thus in order to check whether the truck hit the barrier or not, we will see the distance, d it covers by using the kinematic eqn:

$v'^{2} = v^{2} + 2ad$

Final velocity, v' = 0 m/s

Initial velocity = v

Now,

$0^{2} = 25^{2} + 2\times -4d$

$- 8d = - 625$

d = 78.125 m

Thus the truck will not cross the barrier.

Distance between the barrier and the truck:

100 - 78.125 = 21.875 m

6 0

4 years ago

Read 2 more answers

When designing an experiment a benefit of larger sample sizes would be more____. A.variables B.representative data C.time per gr

castortr0y [4]

<span>When designing an experiment a benefit of larger sample sizes would be more representative data. This larger sample size would lead to perfect result. The correct option among all the options that are given in the question is the second option or option "B". I hope the answer comes to your help.</span>

5 0

3 years ago

Read 2 more answers

Help will mark as brainliest

blagie [28]

Answer:

option no.(a)

Explanation:

is a correct answer.....

4 0

3 years ago