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Paraphin [41]
3 years ago
14

A line has an equation of y = - 3x + 8. What is the y-intercept of the line? Please enter your answer as a coordinate (x, y). *

Mathematics
1 answer:
mina [271]3 years ago
6 0

Answer:

(0, 8).

Step-by-step explanation:

The y intercept occurs when  = 0, so we have the equation:

y = -3(0) + 8

y = 0 + 8

y = 8.

The answer is (0, 8).

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Step-by-step explanation:

4 0
3 years ago
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Estimate then ubtract 4 3/8 1 5/8
timofeeve [1]

Step-by-step explanation:

3/8 = 0.375

5/8 = 0.625

4.375 - 1.625

= 2.75

3 0
3 years ago
Find the equation of the parable in general form by completing the square. Then, state its vertex
lora16 [44]
The parabola will show the vertex in the format: y-k = (x-h)^2, where the vertex point
lies at (h, k).
so \: for \:  {x}^{2}  + 2x - y + 3 = 0
let's first put it in "y =" standard format:
y =  {x}^{2}  + 2x + 3
Since we cannot get a perfect square out of this, we complete the square: a=1, b=2, c=3
(b/2)^2 = (2/2)^2 = 1, so
y =  {(x +1)}^{2} ...\: is \: y =  {x}^{2}  + 2x + 1
So there's +2 leftover, since 3-1=2; so:
y =  {(x + 1)}^{2}  + 2
Now we'll subtract the 2 from both sides to show our vertex:
y - 2 =  {(x + 1)}^{2}
where our vertex (h, k) is at (-1, 2)
6 0
3 years ago
Select the two values of x that are roots of this equation.
VMariaS [17]

Answer:

x = 2, -3

Step-by-step explanation:

x^2 + 2x- 6 = 0\\=>x^2 +3x - 2x- 6 = 0\\=>x(x+3) - 2(x +3) = 0\\=> (x-2)(x+3) = 0\\\\

(x-2)  = 0     or (x+3) = 0

x = 2  or x = -3

Thus, two values of x are x = 2, -3

Note: The options given are incorrect.

4 0
3 years ago
20 points if you help me solved this problem plz it’s urgent someone plz help me I need help! Will mark you as brainiest!
deff fn [24]

Answer:  see below

<u>Step-by-step explanation:</u>

C(x) = 39 when 0 < x ≤ 1.0

C(x) = 63 when 1.0 < x ≤ 2.0

C(x) = 87 when 2.0 < x ≤ 3.0

C(x) = 111 when 3.0 < x ≤ 4.0

C(x) = 135 when 4.0 < x ≤ 5.0

C(x) = 159 when 5.0 < x ≤ 6.0

Based on the information I provided above, the answers are:

a) x= 0.6, C(x) = 1.0

   x = 1.0, C(x) = 39

   x = 1.1,  C(x) = 63

   x = 2.5, C(x) = 87

   x = 3.0, C(x) = 87

   x = 4.8, C(x) = 135

   x = 5.0, C(x) = 135

   x = 5.3, C(x) = 159

b) If C(x) = 87, then 2.0 < x ≤ 3.0

c) Domain (all possible x-values): 0 < x ≤ 6.0

d) Range (all possible y-values): {39, 63, 87, 111, 135, 159}

3 0
3 years ago
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