First we would solve both x’s
3x^2 - 5x
But 3 has the thingy thing (forgot the name haha)
Which means you have to multiply it by itself that many times which would be
3x3=9
So now it would be
9x- 5x = 4x
Which leaves 7 and 4x
Now you may subtract those two
7-4x= 3x
~ Simplifying
-4x + -4 = -7(x + 4)
~ Reorder the terms:
-4 + -4x = -7(x + 4)
~ Reorder the terms:
-4 + -4x = -7(4 + x)
-4 + -4x = (4 * -7 + x * -7)
-4 + -4x = (-28 + -7x)
~ Solving
-4 + -4x = -28 + -7x
~ Solving for variable 'x'.
~ Move all terms containing x to the left, all other terms to the right.
~ Add '7x' to each side of the equation.
-4 + -4x + 7x = -28 + -7x + 7x
~ Combine like terms: -4x + 7x = 3x
-4 + 3x = -28 + -7x + 7x
~ Combine like terms: -7x + 7x = 0
-4 + 3x = -28 + 0
-4 + 3x = -28
~ Add '4' to each side of the equation.
-4 + 4 + 3x = -28 + 4
~ Combine like terms: -4 + 4 = 0
0 + 3x = -28 + 4
3x = -28 + 4
~ Combine like terms: -28 + 4 = -24
3x = -24
~ Divide each side by '3'.
x = -8
~ Simplifying
x = -8
Find the GCF of 80 and 32.
I'd start by identifying possible integer factors of both 80 and 32:
80: {1,2,4,5,8,10,16,20, 40, 80}
32: {1, 2,4, 8, 16, 32}
Working backwards, we see that the first factor that is represented in both lists is 16. Is 80 evenly divisible by 16? Yes; the quotient is 5.
Is 32 evenly divisible by 16? Yes; the quotient is 2.
You could writet 80 + 32 as 16(5 + 2). This is a product equal to 112, just as 80 + 32 = 112.
Answer: it’s the same 110 degrees
Step-by-step explanation: