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Sindrei [870]
3 years ago
5

When you multiply 2/3 by a fraction less than one, how does the product compare to the factor

Mathematics
1 answer:
user100 [1]3 years ago
3 0
The product is less than either of the factors. Multiplying a number < 1 with 2/3 another number < 1, will give a fraction of a fraction, and part of a fraction is an even smaller fraction. Another way of looking at it: Fractions less than one have numerators smaller than their denominators. When multiplying fractions, you multiply across, so multiplying two fractions that are both less than one will always give a numerator much smaller than the denominator, and a larger denominator makes for a smaller number. I hope this helps, but if you have questions, ask.
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translate the sentence into an equation. the sum of 4 times a number and 8 equals 7. use the variable c for the unknown number
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Answer: 4× 8c = 7

Step-by-step explanation:

3 0
3 years ago
One household is to be selected at random from a town. ​ ​The probability that ​the household has a cat is 0.20.2 . ​ ​The proba
dimulka [17.4K]

Answer:

There is a 50% probability that the household has a dog, given that the household has a ​cat.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a household has a cat.

B is the probability that a household has a dog.

We have that:

A = a + (A \cap B)

In which a is the probability that a household has a cat but not a dog and A \cap B is the probability that a household has both a cat and a dog.

By the same logic, we have that:

B = b + (A \cap B)

The probability that the household has a cat or a dog is 0.5

a + b + (A \cap B) = 0.5

The probability that the household has a dog ​is 0.4

B = 0.4

B = b + (A \cap B)

b = 0.4 - (A \cap B)

The probability that ​the household has a cat is 0.2.

A = 0.2

A = a + (A \cap B)

a = 0.2 - (A \cap B)

So

a + b + (A \cap B) = 0.5

0.2 - (A \cap B) + 0.4 - (A \cap B) + (A \cap B) = 0.5

A \cap B = 0.1

What is ​the probability that the household has a dog, given that the household has a ​cat?

20% of the households have a cat, and 10% have both a cat and a dog. So

P = \frac{A \cap B}{A} = {0.1}{0.2} = 0.5

There is a 50% probability that the household has a dog, given that the household has a ​cat.

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3 years ago
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