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3 years ago

What is the product of these numbers?

Mathematics

1 answer:

makkiz [27]3 years ago

8 0

Answer:

0 + 5i

Step-by-step explanation:

Multiply these the way you would any binomials, then replace i² with -1.

(1 +2i)(2 +i) = 1·2 +1·i +(2i)·2 +(2i)·i

= 2 + i + 4i + 2i² . . . . . the partial products

= 2 +5i -2 . . . . . . . . . . after replacement of i² = -1

= 0 +5i

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3 years ago

Transversal problems with equations level 1 (6x+10) (10x+10)

IRISSAK [1]

Answer:

Step-by-step explanation:

Since m||n the sum of given angles is equal to 180 (they are supplementary)

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1 year ago

Which of the following is the point and slope of the equation y - 11 = 3(x + 13)?

4vir4ik [10]

The answer is A.

The equation simplifies to y=3x+50.
So, C is already not an option.

Now we just plug in points to see if the point works for the equation.

A-11=3(-13)+50
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11=11

Thus, this point falls on the line of this equation and is a point.

So, the answer is A.

I hope this helps!

4 0

2 years ago

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If you invested $250 at 16% interest, how much will you have after 18 years?

Whitepunk [10]

After 1st year: 250$:100%=x$:116%, 250$*116%=x$*100%, x=(250*116)/100=290$. After 1st year I will have 290$
After 2nd year: 290$:100%=x$:116%, x=(290*116)/100=336.4$. After 2nd year I will have 336.4$
After 3rd year I will have (336.4*116)/100=390.224$
After 4th yr: (390.224*116)/100=452.65984$
After 5th yr: (452.65984*116)/100=525.085$
After- 6th yr: 609.1$, 7th yr: 706.556$, 8th yr: 819.605$, 9th yr: 950.742$
10th yr: 1102.86$, 11th yr: 1279.32$, 12th yr: 1484.01$, 13th yr: 1721.45$,
14th yr: 1996.88$, 15th: 2316.38$, 16th yr: 2687$, 17th yr: 3116.92$
After 18 years I will have 3615.63$.

8 0

3 years ago

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Work out the size of one of the exterior angles

hodyreva [135]

Given Information :-

⠀

A polygon with 10 sides ( Decagon )

⠀

To Find :-

⠀

The value of one of the exterior angles

⠀

Formula Used :-

⠀

$\qquad \diamond \: \underline{ \boxed{ \pink{ \sf Exterior ~angle = \dfrac {360^\circ}{no. ~of~sides}}}} \: \star$

⠀

Solution :-

⠀

Putting the given values, we get,

⠀

$\sf \dashrightarrow Exterior ~angle = \dfrac{360 ^\circ}{10} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \frac{36 \cancel{0}^\circ}{ \cancel{10}} \: \: \\ \\ \\ \sf \dashrightarrow Exterior ~angle = \underline{ \boxed{ \frak{ \red{36^\circ}}}} \: \star \\ \\$

Thus, the value of the exterior angles of a Decagon is 36°.

⠀

$\underline{ \rule{227pt}{2pt}} \\ \\$

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2 years ago

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