Peaks are the highest points of a graph, there are four peaks, which are on the line that corresponds with July, which would be summer.
The answers to question 1. are four, four, summer.
January is the lowest point of the graph which are between 0 and 10, so the average temperature for January would be around 5 degrees.
The highest peaks ( July) are around the 70 degree line.
The answer s for question 2 are 5 and 70 degrees.
<u>Given</u>:
Given that O is the center of the circle.
AB is tangent to the circle.
The measure of ∠AOB is 68° and we know that the tangent meets the circle at 90°
We need to determine the measure of ∠ABO.
<u>Measure of ∠ABO:</u>
The measure of ∠ABO can be determined using the triangle sum property.
Applying the property, we have;

Substituting the values, we get;

Adding the values, we have;

Subtracting both sides by 158, we get;

Thus, the measure of ∠ABO is 22°
So first you plug 6 into the equation which is 4(6)-10.
Using PEMDAS, you solve what’s in the parenthesis first and you get 24-10.
24-10=14
f(6)=14
Answer:
259.2 cm
Step-by-step explanation:
Just multiply the two numbers