X squared -9<br> -------------------<br> 3x+9

The FitnessGram™ Pacer Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The 20

Travka [436]

5-5+57738+=78875245

100% correct

8 0

3 years ago

Read 2 more answers

What is the equation of line l?

inessss [21]

Y=-3/2L -2. At the Y axis, line L is at -2, so we add that as B or the Y intercept. We can see that the graph goes 2 over to the right and down three, which makes the slope negative and 3/2 (rise/run)

5 0

3 years ago

Both Andrew and Karleigh recorded the distance they ran in x minutes on treadmills. Andrew A 2-column table with 2 rows. Column

mars1129 [50]

Answer:

ex:Speed (S) is the ratio of the distance (D) covered to the time (t) taken.

That is, S = D/t

Suppose Andrew ran a distance D1 in 1 hour (3600 seconds) at a Speed, say S1, we have

S1 = D1/t

We can then say he ran a distance

D1 = t × S1

= 3600S1

Similarly, let's say Karleigh ran a distance

D2 = t × S2

= 3600S2

Let us compare these two, you will notice that the bigger number between S1 and S2 is going to determine the bigger number between D1 and D2.

Let's choose random numbers for S1 and S2 for clarity, say S1 = 5, S2 = 10

D1 = 3600 × 5

= 18000

D2 = 3600 × 10

= 36000

This makes D2 bigger than D1. this is an example i found on the internet.

Step-by-

hope this helps, good luck

7 0

3 years ago

Read 2 more answers

Consider the following hypothesis test:

Gnom [1K]

Answer:

a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.

b. z=1.24. No, it can not be concluded that the population mean is greater than 50.

c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.

Step-by-step explanation:

We have a hypothesis test for the mean, with the hypothesis:

$H_0: \mu\leq50\\\\H_a:\mu> 50$

The sample size is n=55 and the population standard deviation is 6.

The significance level is 0.05.

We can calculate the standard error as:

$\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{55}}=0.809$

For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.

a. If the sample mean is M=52.5, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{52.5-50}{0.809}=\dfrac{2.5}{0.809}=3.09$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

b. If the sample mean is M=51, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51-50}{0.809}=\dfrac{1}{0.809}=1.24$

The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.

c. If the sample mean is M=51.8, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51.8-50}{0.809}=\dfrac{1.8}{0.809}=2.22$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

8 0

3 years ago

A ride sharing service charges $4.25 for every ride, plus $0.30 per mile. If m represents miles, which rule for p(m) models the

stiv31 [10]

Answer: p(m) = .30m + 4.25

Step-by-step explanation:

5 0

2 years ago

X squared -9 ------------------- 3x+9