Unfortunately, you haven't shared the "figure below" that shows the dimensions of this parcel of land. Without being able to calculate the area of the parcel, you cannot really answer this question exactly.
Suppose that the area of the parcel were 6000 square meters. Dividing that by 1500 square meters, we get 4, which represents the number of zebras that can live on this (example) parcel.
Figure out the area of your parcel, in square meters, and thend divide your result by 1500 square meters. This will give your your answer. Please note: your answer will be a COUNT of zebras. "meters" does not belong in this answer.
Find 5.25% of 200
remember
1% of 100=1
therefor
1% of 200=2
just remove the decimal and double it (for this special case of finding percent of 200)
5.25% of 200=5.25 times 2=10.5
answer is 10.5 pounds of copper
(the legit way is 0.0525 times 200=10.5 pound)
10.5lb is answer
Answer:
The scale factor is 4.5
Step-by-step explanation:
Scale factor from ∆RST to ∆XYZ = side length of ∆XYZ / corresponding side length of ∆RST
Thus:
XY corresponds to RS
XY = 45
RS = 10
Therefore:
Scale factor = 45/10 = 4.5
Scale factor from ∆RST to ∆XYZ = 4.5
Kepler's third law described the relation between semi-major axis (or average distance to the star) and
the orbital period (how long it takes to complete one lap) as follows:
a^3 / p^2 = constant
In the case of our Solar system the constant is 1
This means that, for this problem:
a^3 / p^2 = 1
p^2 = a^3
p = a^(3/2)
The semi major axis is given as 101 million km. We need to convert this into AU where 1 AU is approximately 150 million Km
101 million Km = (101x1) / 150 = 0.67 AU
Now, we substitute in the equation to get the orbital period as follows:
p = (0.67)^(3/2) = 0.548 earth years
Answer:
k = 4
Step-by-step explanation:
