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riadik2000 [5.3K]
3 years ago
12

Find Sin A for the triangle. Round to the nearest ten-thousandths

Mathematics
1 answer:
lesantik [10]3 years ago
6 0

Answer:

2.6

Step-by-step explanation:

4 squared - 3 squared =7

Square root 7 equals 2.6 to the nearest tenths

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Write a cubic function whose graph goes through the points: (-5, 0) (1, 0) (2, -2) (4, 0)
Free_Kalibri [48]

Answer:

f(x) = \frac{1}{7}(x+5)(x-1)(x-4)

Step-by-step explanation:

Let the equation of the give cubic function is,

f(x) = p(x - a)(x - b)(x - c)

Here, a, b, c and d are the x-intercepts of the given graph.

Since, x-intercepts given in the graph are x = -5, 1 and 4,

Equation of the curve will be,

f(x) = p(x + 5)(x - 1)(x - 4)

Since, the graph of this function passes through (2, -2) also

-2 = p(2 + 5)(2 - 1)(2 - 4)

-2 = -p(14)

p = \frac{2}{14}

p = \frac{1}{7}

Therefore, equation will be,

f(x) = \frac{1}{7}(x+5)(x-1)(x-4)

5 0
3 years ago
Which equation would you use to find x?
Nitella [24]
You would use B to find X
8 0
4 years ago
What is the value of the discriminant for the quadratic equation -3=-x 2+2x
seraphim [82]
X=3,-1 your answer is right here
3 0
3 years ago
Help math homework both questions
-Dominant- [34]

Answer:

Q-12 The vertical length of the top part of elevator to ground is 0.8484 meters .

Q -14 The glide runway path is 24,752.47 feet .

Step-by-step explanation:

Q - 12

Given as :

The diagonal length of the elevator = e = 1.2 meters

The vertical length of the top part of elevator to ground = x meters

The angle made by elevator with ground = Ф = 45°

<u>Now, According to figure</u>

Sin angle = \dfrac{\textrm perpendicular}{\textrm hypotenuse}

Or, Sin Ф = \dfrac{\textrm x}{\textrm e}

Or, Sin 45° =  \dfrac{\textrm x meters}{\textrm 1.2 meters}

Or, 0.707 × 1.2 meters = x

∴ x =  0.8484 meters

So, The vertical length of the top part of elevator to ground = x = 0.8484 meters

Hence,The vertical length of the top part of elevator to ground is 0.8484 meters .  Answer

Q-14

Given as:

The altitude of decent of plane = H = 10,000 feet

The angle of descend =  Ф = 22°

Let the glide runway path = y feet

<u>Now, According to question</u>

Tan angle = \dfrac{\textrm perpendicular}{\textrm base}

Or, Tan Ф = \dfrac{\textrm H}{\textrm y}

Or, Tan 22° =  \dfrac{\textrm  10,000 feet}{\textrm y feet}

Or, 0.4040 =  \dfrac{\textrm  10,000 feet}{\textrm y feet}

Or, y =  \dfrac{\textrm  10,000 feet}{\textrm 0.4040}

∴   y = 24,752.47

So,The glide runway path = y = 24,752.47 feet

Hence, The glide runway path is 24,752.47 feet . Answer

6 0
3 years ago
What is the lcm of 6 and 4
IceJOKER [234]

12 The least common multiple of 6 and 4 is 12

3 0
3 years ago
Read 2 more answers
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