Solve for y in terms of x. 4y - 2=3(2x + 3y) y=
1 answer:
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Answer:
(B) compress the graph closer to the x-axis
(E) translate the graph to the left
(F) translate the graph up
Step-by-step explanation:
When functions are transformed there are a few simple rules:
- Adding/subtracting inside the parenthesis to the input shifts the function left(+) and right(-).
- Adding/subtracting outside the parenthesis to the output shifts the function up(+) and down(-).
- Multiplying the function by a number less than 1 compresses it towards the x-axis.
- Multiplying the function by a number greater than 1 stretches it away from the x-axis.
This graph has been multiplied by 1/4 which is less than 1. It will be compressed.
This graph has x added to by 3. It will shift left 3 units.
This graph has the output outside of x added to by 6. It will shift 6 units up. See picture below. The original function is red. The new function is blue.
First, we should know exponential formula, for example exp (LnA) =A, for all A>0, and as for logarythm, LnA^p=pLnA, for all A>0, and for all value of p
so y=3^x=exp[Ln(3^x)]=exp(xLn3), let's search the graph of f(x)=exp(xLn3) f is defined in R, and its teminals limits are 0, and + infinity, f' (x) = Ln3.exp(xLn3), it is positif for all value of x, the function is strictly increasing, f(0)=Ln3, please look at the figure 1
the same method with y=2(4.5)^x, we find y=exp[Ln (2(4.5)^x)]=
exp[Ln (2) +Ln(4.5)^x)], because (LnAB=LnA + LnB), so y=2.exp[Ln(4.5)^x)]=2.exp(x[Ln(4.5)]), which domain is R, nd its teminals limits are 0, and + infinity, f' (x)=2.Ln(4.5) exp(x[Ln(4.5)]), which is positif for all value of x, the function is strictly increasing,and then f(0)=2Ln(4.5)
please look the figure 2
so y=3^x=exp[Ln(3^x)]=exp(xLn3), let's search the graph of f(x)=exp(xLn3) f is defined in R, and its teminals limits are 0, and + infinity, f' (x) = Ln3.exp(xLn3), it is positif for all value of x, the function is strictly increasing, f(0)=Ln3, please look at the figure 1
the same method with y=2(4.5)^x, we find y=exp[Ln (2(4.5)^x)]=
exp[Ln (2) +Ln(4.5)^x)], because (LnAB=LnA + LnB), so y=2.exp[Ln(4.5)^x)]=2.exp(x[Ln(4.5)]), which domain is R, nd its teminals limits are 0, and + infinity, f' (x)=2.Ln(4.5) exp(x[Ln(4.5)]), which is positif for all value of x, the function is strictly increasing,and then f(0)=2Ln(4.5)
please look the figure 2
Answer:
The graph of y = f(x) will shift left 6 units, as shown in figure a.
Step-by-step explanation:
A translation means we are able to move the graph of a function up or down - normally called Vertical Translation - and right or left - commonly called Horizontal Translation.
If we replace the graph of y = f(x) with the graph of y = f(x + 6). It means we have added 6 units to the input, meaning the graph y = f(x) will shift left by 6 units as 6 is being added directly to the x, so it is f(x + 6).
For example, if y = x² is the original function and of 6 is directly added to x i.e. f(x + 6), making it y = (x + 6)². So, we can easily observe that there will be a horizontal translation left of 8 units, as shown in figure a.
So, the graph of y = f(x) will shift left 6 units.
Keywords: graph shift, translation
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