Solve for y in terms of x. 4y - 2=3(2x + 3y) y=

Mathematics

1 answer:

yaroslaw [1]2 years ago

8 0

Answer: x3y5

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hopefully this helps!

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Can you help me solve this please

OLga [1]

Answer:

-22+27i

Step-by-step explanation:

$i = \sqrt{ - 1} \\ (3 - 4i)( - 6 + i) \\ = (3 - 4 \sqrt{ - 1} )( - 6 + \sqrt{ - 1} ) \\ = 3( - 6 + \sqrt{ - 1)} - 4 \sqrt{ - 1} ( - 6 + \sqrt{ - 1} ) \\ = - 18 + 3 \sqrt{ - 1} + 24 \sqrt{ - 1} - 4 \\ = - 22 + 27 \sqrt{ - 1} \\ putting \: \: \: \sqrt{ - 1 } = i \\ = - 22 + 27i$

Hope it helps.

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8 0

2 years ago

9/16+5/12= help asap

navik [9.2K]

$\frac{9}{16} + \frac{5}{12} = \frac{27}{48} + \frac{20}{48} = \frac{47}{48}$

8 0

3 years ago

Read 2 more answers

Find the range of the function F(x) = the integral from 0 to x of the square root of 4-t^2 dt

ioda

Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)

If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.

On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.

For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.

Then the range of F(x) is the interval [-π, π].

8 0

2 years ago

Rewrite each fraction in simplest form using the GCF of the numerator and denominator.

Elanso [62]

Answer:

$\sf 6. \quad \dfrac{7}{10}$